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2 years ago

Y = -2x+-3 y = -2x+-3 What do the equations have in common?

Mathematics

2 answers:

geniusboy [140]2 years ago

3 0

Answer:

infinitely many solutions

they have the same equation

Step-by-step explanation:

-2x-3=-2x-3

0=0

Ne4ueva [31]2 years ago

3 0

Answer:

They are the same and have a identical property

Step-by-step explanation:

They are the same equation and they both are showing identical property.

Hope this helps!!!

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The spinner below is spun, then a month of the year is randomly selected. Find the probability of P(unshaded, then a month that

lana [24]

Answer:

C)150

Step-by-step explanation:

P (blue) fraction = 2/8 decimal=.25 percent=25%

P(purple) fraction=0/8 decimal=0 percent =0%

P(not green) fraction=5/8 decimal=.625 percent= 62.5%

P(not brown) fraction=8/8 decimal=1 percent =100%

2)Refer to the table on air travel selected airports. Suppose a flight that arrived at El Centro is selected at random. What is the probability that the flight did not arrive on time? write your answer as a fraction, decimal and percent.

80% on time so 20% are not on time

20/100 ÷ 20 =1/5

20%, .2, 1/5

3)The spinner has 8 sectors labeled with letters. Each sector of the spinner below is the same size, as shown.

If the arrow is spun 400 times , how many times would it be expected to land on a sector labeled B?

A)50 C)150

B)100 D)250

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7 0

2 years ago

Factor completely:<br>64 - y^3

madam [21]

From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is $4^{3}$ , and $y^{3}$ .

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are $a^{3}$ and $b^{3}$ . The difference of those two cubes is:
$a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})$

In our problem, a = 4 (since $a^{3}$ = 64) and b = y (since $b^{3} = y^{3}$ . Plug these values into the rule to find the factor of $64 - y^3$ :
$64 - y^3 \\
= (4 - y)( 4^{2} + 4y + y^{2}) \\
= (4 - y)( 16 + 4y + y^{2})$

-----

Answer: $(4 - y)( 16 + 4y + y^{2})$

8 0

2 years ago

Waylon played defense in 12 soccer games. This was 60% of the total games he played. How many games did Waylon play?

puteri [66]

Answer:

20 games

Step-by-step explanation:

(12/x)=(60/100)

12*100=1200

60x=1200

x=20

4 0