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allsm [11]
3 years ago
5

a cross section of a parabolic glass mirror of the Hubble space telescope shown can be modeled by the graph of the function y=0.

0043x^2 where x and y are measured in meters. Find the domain and range of the function in this situation
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

You need to divide this one :)


Hope this helps

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Evaluate<br> 2^9 over 2^5
s2008m [1.1K]

Answer:

2^4  or 16

Step-by-step explanation:

We know that a^b / a^c = a^(b-c)

2^9 / 2^5

2^(9-5)

2^4  or 16

8 0
3 years ago
Read 2 more answers
A clothing company plans to shear at least 700 sheep today all novices shear the same number of sheep per day and all experts sh
Llana [10]

Answer:

Each Novis share 7 sheep and each Expert share 12 sheep.

Step-by-step explanation:

Here, N represent the number of novices and E represent the number of experts needed for the company to meet its goal,

∵ All novices share the same number of sheep per day and all experts share the same number of sheep per day.

Let the sheep per day by a Novice = x and sheep per day by an expert = y,

So, the total sheep = xN + yE

According to the question,

Total sheep ≥ 700

⇒ xN + yE  ≥ 700,

By here, we have given the inequality for the given scenario,

7N+12E ≥ 700

By comparing,

x = 7 and y = 12

Hence, Each Novis share 7 sheep and each Expert share 12 sheep.

3 0
3 years ago
Suppose the CPI increases this year from 208 to 221. What is the rate of inflation for this year? Round your answer to the neare
guajiro [1.7K]

SOLUTION:

We are to find the rate of inflation in the given question;

The formula to be used is;

Inflation rate =

\frac{\text{CPI}_{present}-CPI_{previous}}{CPI_{previous}_{}}\text{ X 100}\begin{gathered} \frac{221-208}{208}\text{ X }\frac{100}{1} \\  \\ \frac{13}{208}X\frac{100}{1} \\  \\ 6.25\text{ \%} \\ 6.3\text{ \% (nearest tenth of a percentage)} \end{gathered}

CONCLUSION

The inflation rate of CPI that increased from 208 to 221 to the nearest tenth of a percentage is 6.3%.

8 0
1 year ago
A statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after
lana [24]

Answer:

95% confidence interval estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

(a) Lower Limit = 0.486

(b) Upper Limit = 0.624

Step-by-step explanation:

We are given that a statistician is testing the null hypothesis that exactly half of all engineers will still be in the profession 10 years after receiving their bachelor's.

She took a random sample of 200 graduates from the class of 1979 and determined their occupations in 1989. She found that 111 persons were still employed primarily as engineers.

Firstly, the pivotal quantity for 95% confidence interval for the population proportion is given by;

                         P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of persons who were still employed primarily as engineers  = \frac{111}{200} = 0.555

           n = sample of graduates = 200

           p = population proportion of engineers

<em>Here for constructing 95% confidence interval we have used One-sample z proportion test statistics.</em>

So, 95% confidence interval for the population proportion, p is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level of

                                                 significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

 = [ 0.555-1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } , 0.555+1.96 \times {\sqrt{\frac{0.555(1-0.555)}{200} } } ]

 = [0.486 , 0.624]

Therefore, 95% confidence interval for the estimate for the proportion of engineers remaining in the profession is [0.486 , 0.624].

7 0
3 years ago
Which equation represents the graph​
elena55 [62]
aaanswer : D) y=2x
8 0
3 years ago
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