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asambeis [7]
2 years ago
13

The cost of 3 slices of pizza is $4.89. What is the cost of each slice of pizza? $1.63 $1.89 $2.45 $2.88

Mathematics
2 answers:
allsm [11]2 years ago
5 0

1.63 just divided the total by 3

castortr0y [4]2 years ago
3 0

1.63

4.89 divided by 3 = 1.63

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A meteor crater is 4000 feet in diameter. approximate the distance around the crater.
Troyanec [42]

9514 1404 393

Answer:

  12,566 ft ≈ 2.38 miles

Step-by-step explanation:

The circumference of a circle is given by the formula ...

  C = πd

For a diameter of 4000 ft, the circumference of a circular crater is about ...

  C = (4000 ft)(3.141593) ≈ 12,566 ft

At 5280 ft per mile, that distance is about ...

  (12,566 ft)/(5280 ft/mi) ≈ 2.38 mi

The distance around the crater is about 12,566 ft or 2.38 miles.

3 0
2 years ago
Pls answer! Dylan spots an airplane on radar that is currently approaching in a straight line, and
anastassius [24]

Answer:

13510 ft

Step-by-step explanation:

I have attached a triangle diagram to depict this situation.

From the diagram, we see that distance between A and B is denoted by x.

Now, from trigonometric ratios in this type of triangle, let's first find y.

6400/y = tan 36

y = 6400/tan 36

y = 8808.84 ft

Now, we can find x from;

6400/(8808.84 + x) = tan 16

6400/tan 16 = 8808.84 + x

22319.452 = 8808.84 + x

x = 22319.452 - 8808.84

x ≈ 13510 ft

5 0
3 years ago
Use the number line to add or subbtract integers please help me with this
Digiron [165]

Answer:

a)=+2 b)=1

Step-by-step explanation:

A positive plus a negative is equal to a positive a

8 0
3 years ago
A random sample of 20 recent weddings in a country yielded a mean wedding cost of $ 26,388.67. Assume that recent wedding costs
Makovka662 [10]

Answer:

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) For the interpretation of the result, option D is correct.

We can be​ 95% confident that the mean​ cost, μ​, of all recent weddings in this country is somewhere within the confidence interval.

c) Option B is correct.

The population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Step-by-step explanation:

Sample size = 20

Sample Mean = $26,388.67

Sample Standard deviation = $8200

Confidence Interval for the population mean is basically an interval of range of values where the true population mean can be found with a certain level of confidence.

Mathematically,

Confidence Interval = (Sample mean) ± (Margin of error)

Sample Mean = 26,388.67

Margin of Error is the width of the confidence interval about the mean.

It is given mathematically as,

Margin of Error = (Critical value) × (standard Error of the mean)

Critical value will be obtained using the t-distribution. This is because there is no information provided for the population mean and standard deviation.

To find the critical value from the t-tables, we first find the degree of freedom and the significance level.

Degree of freedom = df = n - 1 = 20 - 1 = 19.

Significance level for 95% confidence interval

(100% - 95%)/2 = 2.5% = 0.025

t (0.025, 19) = 2.086 (from the t-tables)

Standard error of the mean = σₓ = (σ/√n)

σ = standard deviation of the sample = 8200

n = sample size = 20

σₓ = (8200/√20) = 1833.6

99% Confidence Interval = (Sample mean) ± [(Critical value) × (standard Error of the mean)]

CI = 26,388.67 ± (2.093 × 1833.6)

CI = 26,388.67 ± 3,837.7248

99% CI = (22,550.9452, 30,226.3948)

99% Confidence interval = (22,550.95, 30,226.40)

a) 95% confidence interval for the mean​cost, μ​, of all recent weddings in this country = (22,550.95, 30,226.40)

.The​ 95% confidence interval is from $22,550.95 to $30,226.40.

b) The interpretation of the confidence interval obtained, just as explained above is that we can be​ 95% confident that the mean​ cost, μ​,of all recent weddings in this country is somewhere within the confidence interval

c) A further explanation would be that the population mean may or may not lie in this​ interval, but we can be​ 95% confident that it does.

Hope this Helps!!!

4 0
2 years ago
There were 3995 more hits on the school's website in January than February. February had 9854 hits. How many hits did the school
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In both months they had 23,703 and in January they had 13,849
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