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antiseptic1488 [7]
3 years ago
11

Find the rate of change for the interval [5,15]

Mathematics
1 answer:
Aleks04 [339]3 years ago
3 0
Left side goes up 5 right side goes up 7

The rate of change between 5,15 is 10
You might be interested in
Find the slope intercept form of the equation of the line through the points(2,-4) parallel to the line 8x+2y+2=0
Margarita [4]

Answer:

y = -4x + 4

Step-by-step explanation:

8x+2y+2=0

turn that into slope intercept form:

y = -4x - 1

a parallel line has the same slope, but different y-intercept

y = -4x + b

put (2,-4) into the equation

-4 = -4(2) + b

you get b=4

final product:

y = -4x + 4

3 0
3 years ago
( Will hand out brainiest) A California condor left its cliff-side nest and soared downwards at a rate of 16 meters per second.
svet-max [94.6K]

First calculate the distance covered going down:

d_down = (16 m / s) * 8 s = 128 m

 

Then the distance going up is:

d_up = 71 m

 

So the distance from the ledge to the nest is:

d = 128 m – 71 m = 57 m

 

Therefore the elevation is:

<span>elevation = 1364 m + 57 m = 1421 m</span>

4 0
2 years ago
I HAVE 10 MIN LEFT CAN SOMEONE HELP ME WITH A FEW OF THESE OR ALL OF EM?
FinnZ [79.3K]
I will help you but I need to know what you need help with , find the area or volume?
4 0
2 years ago
What is 1556 rounded to the nearest thousand
fgiga [73]
Greetings!

"<span>What is 1556 rounded to the nearest thousand?"...

The thousand place value number is in bold: 1556.

Since the number to the right of the bold number is 5 or greater, we round up.

1556 rounded from the thousand place value is 2000.

Hope this helps.
-Benjamin</span>
6 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
2 years ago
Read 2 more answers
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