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3 years ago

Earthworms contain all of the following organisms except a

Biology

2 answers:

Leno4ka [110]3 years ago

7 0

B. is the answer. Earthworms do not have skeletons.

S_A_V [24]3 years ago

4 0

I believe skeletal system but im not 100% positive

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4 years ago

2. What is an example of something studied on the molecular level (as opposed to the atomic level)?

Dmitriy789 [7]

Answer:

Something studied on the molecular level is the water.

Explanation:

Water is a molecule formed by two hydrogen atoms and one oxygen atom, whose chemical representation is H₂O. It is a molecule whose polarity makes it a universal solvent of other polar molecules.

The molecular level corresponds to the level of organization where two or more atoms unite to form molecules or substances, united by chemical bonds. H₂O is studied at this level due to its chemical structure.

With respect to other options:

Hydrogen and oxygen are atoms, and correspond to the level of atomic organization.
Protons are particles that are part of an atom, and correspond to the subatomic level.

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3 years ago

Describe the process of how water freezes

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3 years ago

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The climatic factors which affect a biome are greatly influenced by

Basile [38]

The biome is characterized by climate, temperature, and rainfall. The climatic factors that intervene are the altitude, latitude, and types of soil. Latitude determines temperature and seasonality and defines polar, subpolar, temperate, subtropical and tropical climates. Precipitation and latitude determine wet, sub-humid, dry or seasonal, semi-arid and arid types. The altitude determines the basal, premontane, montane, alpine and snow types. And only soil types are a determining factor in the influence of climatic factors and their variation and behavior within the biome.

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3 years ago

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The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

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3 years ago