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Korvikt [17]
3 years ago
12

Find the perimeter of a regular octagon if one of its sides is x + 6 and another side is 14 – x.

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

  80 units

Step-by-step explanation:

The sides of a regular octagon are all the same length.

  x +6 = 14 -x

  2x = 8 . . . . . . add x-6

  x = 4

  x+6 = 10 . . . . the length of each of the 8 sides

P = 8s = 8(10) = 80

The perimeter of the octagon is 80 units.

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I NEED HELP WITH THEM ALL PLEASE
PilotLPTM [1.2K]

Answer:

17. 11/20

18. 75cm^2

19. 45

20. a. 93 b. 93 c. 90,94

Step-by-step explanation:

I suggest putting more points for it next time that's 4 questions and saying please makes you sound desperate.

Hope this helped! Have a nice day!

8 0
3 years ago
PLEASE HELP this is due tomorow and im not finsihed yet :(
pychu [463]
0.02 = 2%
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7 0
3 years ago
Identify each pair of angles named below as adjacent angles or vertical angles.
liq [111]

Answer:

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-Todo<3

Step-by-step explanation:

6 0
2 years ago
Which term completes the product so that it is the difference of squares?
FromTheMoon [43]

Answer:

the answer is  3

Step-by-step explanation:

(-5x-3)(-5x+3)=(5x)^2 - (3)^2

A difference of squares is the difference of two squared terms.

We have

a^2 - b^2

We can factorize the difference of squared terms like this:

a^2-b^2 = (a+b)(a-b)

We have (-5x-3)(-5x+3)

Lets prove it:

(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)

(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)

(-5x-3)(-5x+3) = 25x^2-15x+15x-9

(-5x-3)(-5x+3) = 25x^2-9

(-5x-3)(-5x+3) = (5x)^2 - (3)^2

6 0
3 years ago
Read 2 more answers
Multiply.<br> 2 1/7 x 3 2/3<br><br> Answer with a mixed number in the simplest form
viva [34]

Answer:

7 6/7

Step-by-step explanation:

2\frac{1}{7} × 3\frac{2}{3} =

\frac{15}{7} × \frac{11}{3} =

\frac{165}{21} =

7\frac{6}{7}

4 0
2 years ago
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