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2 years ago

If f(x) = 3a|4x - 4| - ax, where a is some constant not equal to zero, find f '(1)

2 answers:

7 0

The slope of an absolute function at the point where it evaluates to zero is undefined.
Here, when x=1, so |4x-4|=|4-4|=|0|, the slope is undefined. This is where the vertex of the "V" on the graph of the absolute value function.

hammer [34]2 years ago

3 0

Answer:

Differential does not exist.

Step-by-step explanation:

given function,

f(x) = 3 a|4 x - 4| - ax

opening the function

f(x) = 3 a(4 x - 4) - ax and f(x) = - 3 a(4 x - 4) - ax

f'(x) = 12 a - a and f(x) = -12 a - a

f'(x) = 11 a and f(x) = -13 a

f'(1⁺) = 11 a and f(1⁻) = -13 a

hence,

f'(1⁺) ≠ f(1⁻)
so, Differential does not exist.

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Find each value if f(x) = 2x - 1 and g(x) = 2 - x2.

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3 years ago

Please help!!! I’m so confused on how to solve this!

-Dominant- [34]

Let's first write the equation given

x²+6x-13=0

They have told us to use "Completing the square" method.

So we need write x²+6x-13 as a whole square.

x²+6x-13=0

x²+(2*3*x)-9-4 = 0

x²+(2*3*x)-3²=4

Now we can write the LHS as:

(x - 3)²=2²

Hence,

x-3 can either be 2 or -2

Now,

x - 3=2

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Or,

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8 0

3 years ago

Read 2 more answers

Please math , help

Furkat [3]

Answer:

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

Step-by-step explanation:

Mean of the batch:

The mean of the batch is the sum of all values divided by the number of items. So

$M = \frac{199+204+201+197+195+204+200}{7} = 200$

Mean in the desired interval.

Standard deviation:

Square root of the sum of the difference squared between each term and the mean, divided by the number of items. So

$S = \sqrt{\frac{(199-200)^2+(204-200)^2+(201-200)^2+(197-200)^2+(195-200)^2+(204-200)^2+(200-200)^2}{7}} = 1.18$

As both the mean and standard deviation are in the desired ranges, the tool passes the technical control.

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3 years ago

Amos, peter, and Carlos begin running around a circular track the same time, from the same start line. It takes Amos 12 minutes

umka2103 [35]

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3 years ago

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When Samuel commutes to work, the amount of time it takes him to arrive is normally distributed with a mean of 32 minutes and a

k0ka [10]

Answer:

$z=\frac{x-\mu}{\sigma}$

And we can find the nnumber of deviations from the mean for each limit given:

$z_1 = \frac{17-32}{5} = -3$

$z_2= \frac{47-32}{5} = 3$

So we are 3 deviation from the mean and using the empirical rule we know that within 3 deviations from the mean we have 99.7% of the values

Step-by-step explanation:

Let X the random variable that represent the amount of time it takes him to arrive, and for this case we know the distribution for X is given by:

$X \sim N(32,5)$

Where $\mu=32$ and $\sigma=5$

We want to find this probability:

$P(17$

And we can use the z score formula given by:

$z=\frac{x-\mu}{\sigma}$

And we can find the nnumber of deviations from the mean for each limit given:

$z_1 = \frac{17-32}{5} = -3$

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8 0

2 years ago