Which of these shows a reflection between Graph A and Graph B?

Mathematics

1 answer:

Dovator [93]3 years ago

3 0

Reflection is creating a mirror image, and when we reflect, we reflect over an axis. Suppose we're holding a mirror with these images. A is not the answer because All that was done was translation downwards. C is not the answer because this was translated as well. D is not the answer because the image is not being reflected, it's being rotated. The only graph the shows a mirror image is B.

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(? x 3) - 3 = 15<br><br>help pls and i need the steps :/

marishachu [46]

Answer:

Step-by-step explanation:

Lets make $x$ be the ? in the equation.

That becomes ( $x$ x 3) - 3 = 15.

First you have to add 3 on both sides. After doing that it gets to ( $x$ x 3) = 15 - 3.

Then you simplify it to 3 $x$ = 12.

Now you divide 3 on both sides. That gets to $x$ = 4 after doing it.

Hope this helped! If not, please let me know! <3

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B I think I’m not sure

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Read 2 more answers

How to find variables of these #2 & #3

Lubov Fominskaja [6]

So... hmmm if you check the first picture below, for 2)

we could use the proportions of those small, medium and large similar triangles like $\bf \cfrac{small}{large}\qquad \cfrac{x}{12}=\cfrac{6}{x}\impliedby \textit{solve for "x"}
\\\\\\
\cfrac{small}{large}\qquad \cfrac{z}{18}=\cfrac{6}{z}\impliedby \textit{solve for "z"}
\\\\\\
\cfrac{large}{medium}\qquad \cfrac{y}{12}=\cfrac{18}{y}\impliedby \textit{solve for "y"}$

now.. for 3) will be the second picture below

$\bf \cfrac{large}{medium}\qquad \cfrac{x+10}{2\sqrt{30}}=\cfrac{2\sqrt{30}}{10}\impliedby \textit{solve for "x"}
\\\\\\
\textit{now, because you already know what "x" is, we can use it below}
\\\\\\
\cfrac{large}{small}\qquad \cfrac{z}{x}=\cfrac{x+10}{z}\impliedby \textit{solve for "z"}
\\\\\\
\textit{and let us use "x" again below}
\\\\\\
\cfrac{small}{medium}\qquad \cfrac{y}{10}=\cfrac{x}{y}\impliedby \textit{solve for "y"}$

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C = 3/4T+2

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What does 3t+5=4t? prove t =7 ??

Nimfa-mama [501]

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