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3 years ago

Write the equation of the linepasses through the points (2-4) and (-3, 16)

Mathematics

2 answers:

kobusy [5.1K]3 years ago

8 0

Answer:

y=-4x+4

Step-by-step explanation:

solve for the slope y2-y1 over x2-x1

16-(-4) over -3-2 =-4

plug into point slope form y-y1=m(x-x1)

y-(-4)=-4(x-2)

morpeh [17]3 years ago

3 0

Answer:

y=-4x+4

Step-by-step explanation:

So use the formula y2-y1/x2-x1 and enter the given points

16-(-4)/-3-2

= 16+4/-5

=20/-5

= -4

Slope= -4

y=-4x+b enter 1 given point (2,-4)

-4=-8+b

b=4

so the slope int. form is

y=-4x+4

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