The general form of the quadratic equation is :
The discriminant is :
And the general solution is :
![x=\frac{-b\pm\sqrt[]{D}}{2\cdot a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7BD%7D%7D%7B2%5Ccdot%20a%7D)
So, there are 3 situations for D
1. D = 0
So, the roots of a quadratic equation are two similar roots
2. D > 0
so, roots of a quadratic equation are two different roots
3. D < 0
so, roots of a quadratic equation are not real, two comlex roots
Answer:
Counting my money
Step-by-step explanation:
I believe the correct answer from the choices listed above is option A. Given a segment with endpoints A and B and the steps given above, the figure that you can construct would be a perpendicular bisector. <span>The </span>perpendicular bisector<span> of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.</span>
