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Amanda [17]
3 years ago
6

Find the center and radius of the circle with the equation. Please show work!

Mathematics
1 answer:
mina [271]3 years ago
3 0

Answer:

<h2>(1, -2)</h2>

Step-by-step explanation:

The equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have:

x^2-2x+y^2+4y=4\qquad\text{add}\ 1^2\ \text{and}\ 2^2\ \text{to both sides}\\\\x^2-2x+1^2+y^2-2(-2)(y)+2^2=2(1^2)(2^2)\qquad\text{use}\ (a\pm b)^2=a^2\pm2ab+b^2\\\\(x-1)^2+(y-(-2))^2=8\\\\h=1,\ k=-2\to(1,\ -2)

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and to figure this out you need to divide 325 by 5
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8 0
3 years ago
The velocity time graph for a cycle is shown
Assoli18 [71]

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Step-by-step explanation:

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3 years ago
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Marrrta [24]
This is an odd problem. The length and width look like they should be interchanged. Anyway I'll solve it and we'll talk about the results.
(x +7) (x + 3) = 396
x^2 + 7x + 3x + 21 = 396
x^2 + 10x + 21 = 396 Subtract 21 from both sides.
x^2 + 10x = 396 - 21
x^2 + 10x = 375
x^2 + 10x - 375 = 0 This probably factors.
(x + 25)(x - 15)
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Check
=====
Area = L * W = 18 * 22 = 496. It does check.
22 should be the length

18 should be the width.
3 0
3 years ago
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