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wolverine [178]
3 years ago
6

Find the area of a parallelogram with a base of 10cm and height of 5cm. Write the area first and show your work.

Mathematics
1 answer:
STatiana [176]3 years ago
5 0

Answer:

50 cm^{2}

Step-by-step explanation:

The equation to finding the area of a parallelogram is base*height.

Plugging in those numbers gives us 10 cm*5 cm.

That is 50cm^{2}.

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Multiple

Step-by-step explanation:

You put the equation in slope intercept form, therefore, the solutions are the entire line!

Every point on the line can be considered a solution.

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3 years ago
~~~~~~~~~~~`````````````````
bixtya [17]

Answer:

Step-by-step explanation:

(-3/4)x + 9 = (-1/2)x + 8

        9 - 8 =  (-1/2)x + (3/4)x

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              x = 4

y = (-3/4)4 + 9

y = -3 + 9

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2 years ago
A teacher surveys 30 students on the the number of books they read over the summer.The data are represented in the box plot what
Margaret [11]

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Wheres the plot?

Step-by-step explanation:

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3 years ago
The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
PLEASE HELP FIRST GETS BRAINLIEST
asambeis [7]
I believe that this would be representative.
3 0
3 years ago
Read 2 more answers
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