Area of a sphere = 4(pi)(r)^2
Reverse the equation to find the radius (r)
The answer will be in pi form
32/81(pi)
8/20.25(pi)
Square root of 8/20.25(pi) = radius
r = 2.8(rounded)/4.5(pi)
:)
Answer:
77.2°
Step-by-step explanation:
Consider the triangle JKR.
∠KJR=108.6 (lies on the same line as ∠RJA, angles on a straight line add up to 180)
All the angles in a triangle add up to 180, so:
∠JKR+∠KJR+∠JRK=180
∠JKR+108.6+32.8=180
∠JKR=38.6=∠RKA
Consider ∠RKA. This angle stands on the same arc as ∠RCA.
Since the angle at centre is twice the angle at circumference, 2(∠RKA) = ∠RCA.
2(∠RKA) = ∠RCA
2(38.6)=∠RCA
∠RCA=77.2°
Answer:
The slope of the line is
.
-
Step-by-step explanation:
☆Remember:

☆Just plug it in with 2 sets of coordinate points.

Answer:
3/8
Step-by-step explanation:
Just subtract 5/8 by 2/8 and you get 3/8
X² - 3x - 10
x² = x * x
10 can be factored:
1 x 10 ⇒⇒⇒ difference between factors = 9
2 x 5 ⇒⇒⇒ difference between factors = 3 ⇒ (The correct pair)
(x-5)(x+2) = x(x+2) - 5(x+2)
= x² + 2x - 5x - 10
= x² - 3x - 10
∴ x - 5 = 0 ⇒⇒⇒ x = 5
x + 2 = 0 ⇒⇒⇒ x = -2
I have attached <span>algebra tiles for the given equation.</span>