Answer:
x=-4 , Extraneous
Step-by-step explanation:
Given : Equation - 
To classify : The given equation as extraneous or non-extraneous ?
Solution :
An extraneous solution is one that we arrive at that will not work in the equation.
For rational equations, extraneous solutions are ones that will cause the denominator to be 0.
So, first we solve the given equation

Taking LCM to LHS

Cancel (x+4) both side,

Cross multiply,


Now, if we put x=-4 in the equation the denominator is zero.
Therefore, It is an extraneous solution.