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2 years ago

3x^2 - 5x + 12 5x^2 + x -11

1 answer:

8 0

Are u trying to solve the equations as a system of equations cause if you are the point where they are equal is when x=-(3+/-(sqrt 55))/2

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How do I solve for n? 13=n-8

choli [55]

N in (-oo:+oo)

-13 = n-8 // - n-8

8-n-13 = 0

-n-5 = 0 // + 5

-n = 5 // * -1

n = -5

n = -5

3 0

3 years ago

Read 2 more answers

What is the solution to the equation √8x=√4+2x?

dolphi86 [110]

Answer:

0.3333333333333...........

7 0

3 years ago

The swimming pool is opening hours a day the pool manager must divide pool time equally among five groups camp; camp swim team,

ale4655 [162]

Answer:

1.6 hours

Step-by-step explanation:

Number of opening hours a day = 8

Number of groups = 5

Dividing the number of opening. Hours equally among the 5 groups :

8 hours / 5

= 1.6 hours per group per day

4 0

2 years ago

The___ of an angle is the ratio of the opposite leg length to the hypotenuse length.

ozzi

The answer would be sine

7 0

2 years ago

Read 2 more answers

The total cost (in hundreds of dollars) to produce x units of a product is c(x) = (3x-2) / (8x+1), find the average cost for eac

olya-2409 [2.1K]

Answer:

a) $\frac{74}{10025}$

b) $\frac{3x-2}{x(8x+1)}$

c) $\frac{-24x^2+32x-2}{(8x^2+x)^2}$

Step-by-step explanation:

For total cost function $c(x)$ , average cost is given by $\frac{c(x)}{x}$ i.e., total cost divided by number of units produced.

Marginal average cost function refers to derivative of the average cost function i.e., $\left ( \frac{c(x)}{x} \right )'$

Given: $c(x)=\frac{3x-2}{8x+1}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

At x = 50 units,

$\frac{c(50)}{50}=\frac{150-2}{50(400+1)}=\frac{148}{50(401)}=\frac{74}{10025}$

Average cost = $\frac{c(x)}{x}=\frac{3x-2}{x(8x+1)}$

Marginal average cost:

Differentiate average cost with respect to $x$

Take $f=3x-2\,,\,g=8x^2+x$

using quotient rule, $\left ( \frac{f}{g} \right )'=\frac{f'g-fg'}{g^2}$

Therefore,

$\left ( \frac{c(x)}{x} \right )'=\left ( \frac{3x-2}{8x^2+x} \right )'\\=\left ( \frac{3(8x^2+x)-(16x+1)(3x-2)}{(8x^2+x)^2} \right )\\=\frac{24x^2+3x-48x^2-3x+32x+2}{(8x^2+x)^2}\\=\frac{-24x^2+32x-2}{(8x^2+x)^2}$

3 0

3 years ago