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ladessa [460]
2 years ago
13

The functions f and g are defined by f: x = 4 - x and g: x = hx² + k. If the composite function gf is given by gf: x + 2x² - 16x

+ 26, find
(a) the value of h and of k,​
Mathematics
1 answer:
kozerog [31]2 years ago
5 0

Answer:

Step-by-step explanation:

f(x) = 4-x

g(x) = hx^{2}+k

g(f(x)) = 2x^{2}-16x+26

so put  f(x)  in g(x)

h(4-x)^{2}+k

h((4-x)(4-x) + k

h(x^{2}-8x+16)+k

if h = 2 , then

2x^{2}-16x+32 + k

and we want 26  instead of 32 so subtract 6 so K = (-6)

2x^{2}-16x+32 + (-6)

2x^{2}-16x+32 - 6

2x^{2}-16x+26

h=2

k=(-6)

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3 years ago
There are 14 students in an art class. Mr.
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3 years ago
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Iteru [2.4K]

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10 < \sqrt{111} < 11

Step-by-step explanation:

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5 0
3 years ago
A.
Reptile [31]

Answer:

The real zeros of f(x) are x = 0.3 and x = -3.3.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this problem, we have that:

f(x) = x^{2} + 3x - 1

So

a = 1, b = 3, c = -1

\bigtriangleup = 3^{2} - 4*1*(-1) = 13

x_{1} = \frac{-3 + \sqrt{13}}{2*1} = 0.3

x_{2} = \frac{-3 - \sqrt{13}}{2*1} = -3.3

The real zeros of f(x) are x = 0.3 and x = -3.3.

7 0
3 years ago
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rodikova [14]

Answer:

100,000 days

Step-by-step explanation:

1,000,000 / 10 = 100,000 days.

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3 years ago
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