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ladessa [460]
2 years ago
13

The functions f and g are defined by f: x = 4 - x and g: x = hx² + k. If the composite function gf is given by gf: x + 2x² - 16x

+ 26, find
(a) the value of h and of k,​
Mathematics
1 answer:
kozerog [31]2 years ago
5 0

Answer:

Step-by-step explanation:

f(x) = 4-x

g(x) = hx^{2}+k

g(f(x)) = 2x^{2}-16x+26

so put  f(x)  in g(x)

h(4-x)^{2}+k

h((4-x)(4-x) + k

h(x^{2}-8x+16)+k

if h = 2 , then

2x^{2}-16x+32 + k

and we want 26  instead of 32 so subtract 6 so K = (-6)

2x^{2}-16x+32 + (-6)

2x^{2}-16x+32 - 6

2x^{2}-16x+26

h=2

k=(-6)

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8 0
3 years ago
Work out the length of X.
vlabodo [156]

Answer:

By Pythagoras theorem

H^2=P^2+B^2

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6 0
2 years ago
THIS IS FOR MY TEST PLEASE HELP
AVprozaik [17]
2(3x+4y) = 2(24)
6x+8y = 48
Add both the equations
6x + 8y = 48
+ x - 8y = -20
—————————
7x = 28
x = 28/7
x = 4

Plug in this value in the second equation

(4) - 8y = -20
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y = -24/-8
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Therefore:
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7 0
3 years ago
Why is the value of q?
Rudiy27

Given:

QSR is a right triangle.

QT = 10

TR = 4

To find:

The value of q.

Solution:

Hypotenuse of QSR = QT + TR

                                 = 10 + 4

                                 = 14

Geometric mean of similar right triangle formula:

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{14}{q} =\frac{q}{4}

Do cross multiplication.

$\Rightarrow14\times 4 =q\times q

$\Rightarrow 56 =q^2

Switch the sides.

$\Rightarrow q^2 =56

Taking square root on both sides.

\Rightarrow q =2 \sqrt{14}

The value of q is 2 \sqrt{14}.

8 0
3 years ago
Question 4 help please!
Nadusha1986 [10]

I think the answer is zero
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