Who now that I do now is cus I am in 5 grade

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

Answer:

The answer is 33/5 I will explain below

Step-by-step explanation:

There are two steps to this first you multiply your whole number which is 6 by the denominator or bottom number in your fraction which is the 5.

Then the second step would be to add your numerator or top number in your fraction to the answer you got from the first step. You would get 33 after step 2

Then you basically keep the the denominator and you end up with 33/5!

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The dividend is 36.75 and the divisor is 2.5

Helen [10]

36.75/2.5= 14.7
_______
2.5| 36.75

Move the decimal to the right

14.7
______
25| 367.5
-25
117
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175
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0

Sorry I can't show it better...

6 0

3 years ago

Five cards are dealt from a standard 52-card deck. (a) What is the probability that we draw 1 ace, 1 two, 1 three, 1 four, and 1

Rudik [331]

Answer:

Step-by-step explanation:

As there are total 52 cards in a deck and we have to draw a set of 5 cards, we can use the formula of combination to find the total number of possible ways of drawing 5 cards.

Number of ways to draw 5 cards = $N_T$

$N_T\;=\;({}^NC_k)\\\\N_T\;=\;({}^{52}C_5)\\\\N_T\;=\;2,598,960$

(a) Assuming the cards are drawn in order (would not affect the probability). The of getting Ace, 2, 3, 4 and 5 can be obtained by multiplying the probability of getting cards below 6 (20/52) with the probability of getting 5 different cards (4 choices for each card).

$P(a)\;=\;\frac{20}{52}*\frac{4}{52}*\frac{4}{51}*\frac{4}{50}*\frac{4}{49}*\frac{4}{48}\\\\P(a)\;=\; 1.3133*10^{-6}$

(b) For a straight we require our set to be in a sequence. The choices for lowest value card to produce a sequence are ace, 2, 3, 4, 5, 6, 7, 8, 9, or 10. Hence, the number of ways are $({}^{10}C_1)$ .

For each card we can draw from any of the 4 sets. It can be described mathematically as: $({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)*({}^{4}C_1)\;=\;[({}^{4}C_1)^5]$