The answers for this task are gotten in most cases by Careful Observation of Liam DeWitt's Bank Account Information.
<h3>
What is a Bank Account Information?</h3>
A bank account information refers to all the details present on or which can be deduced from one's statement or record of banking activities..
Liam's Average Daily Balance is: Total sum of balance each day divided by the number of days. That is
(250+87+1300+470-200+34.76+102.71+45.90+84.60)/9
ADB= $241.66
B) Liam's Monthly Periodic Rate (MPR) is the Annual Interest Rate divided by the number of periods. In this case, that will be:
19.8%/12
MPR = 1.65%
C) Liam's Finance Charge is (Average Daily Balance * APR)/365.
That is (241.66 * 19.8)/365 = 13.11%
D) Liam's New Balance is calculated by removing new inflow from old balance. That is
(250+87.60+1,300+470.63+34.76+102.71+45+848.60)-3,240.5
= $-101.20
E) Liam's Available Line of Credit is clearly stated as $4,000.
See the link below for more about Bank Account Information:
brainly.com/question/15525383
Answer:
acute-angled
Step-by-step explanation:
It doesn't have a right angle and one of its corners isn't for than 90 degrees
Answer:
-2, 8/3
Step-by-step explanation:
You can consider the area to be that of a trapezoid with parallel bases f(a) and f(4), and width (4-a). The area of that trapezoid is ...
A = (1/2)(f(a) +f(4))(4 -a)
= (1/2)((3a -1) +(3·4 -1))(4 -a)
= (1/2)(3a +10)(4 -a)
We want this area to be 12, so we can substitute that value for A and solve for "a".
12 = (1/2)(3a +10)(4 -a)
24 = (3a +10)(4 -a) = -3a² +2a +40
3a² -2a -16 = 0 . . . . . . subtract the right side
(3a -8)(a +2) = 0 . . . . . factor
Values of "a" that make these factors zero are ...
a = 8/3, a = -2
The values of "a" that make the area under the curve equal to 12 are -2 and 8/3.
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<em>Alternate solution</em>
The attachment shows a solution using the numerical integration function of a graphing calculator. The area under the curve of function f(x) on the interval [a, 4] is the integral of f(x) on that interval. Perhaps confusingly, we have called that area f(a). As we have seen above, the area is a quadratic function of "a". I find it convenient to use a calculator's functions to solve problems like this where possible.