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OLga [1]
2 years ago
11

Given: E is the midpoint of and ABCD is a rectangle. Prove: △ABE≅△DCE.

Mathematics
1 answer:
andrezito [222]2 years ago
6 0

Answer:

AE = ED/////  A MIDPOINT DIVIDES A SEGMENT INTO TWO CONGRUENT SEGMENTS

AB = DC ///// OPPOSITE SIDES OF A RECTANGLE ARE CONGRUENT

<A IS A RIGHT ANGLE ///// THE INTERIOR ANGLES OF A RECTANGLE ARE RIGHT ANGLES

<D IS A RIGHT ANGLE ///// THE INTERIOR ANGLES OF A RECTANGLE ARE RIGHT ANGLES

<A = <D ///// ALL RIGHT ANGLES ARE CONGRUENT

TRIANGLES ABE = DCE ///// SAS

Hope this might help you.

Step-by-step explanation:

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below is a graph of a logarithmic function, identify it key characteristics. match accordingly.that is the question and can you
Zolol [24]

End behavior: f. As x -> 2, f(x) -> ∞; As x -> ∞, f(x) -> -∞

x-intercept: a. (3, 0)

Range: p. (-∞, ∞)

The range is the set of all possible y-values

Asymptote: x = 2

Transformation: l. right 2

with respect to the next parent function:

g(x)=\log _{\frac{1}{3}}(x)

Domain: g. x > 2

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4 0
1 year ago
Kamil has 72 baseball cards. He wants to put the cards
mars1129 [50]
You would use 72/9 , ( division ).
6 0
2 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
3 years ago
The value of a computer is given by the expression 2000+(-200t) where t is the time in years.
Rashid [163]

If it was one year it would be 2200 and you just keep adding 200 for each year.

5 0
3 years ago
Data from the Centers for Medicare and Medicaid Services indicates that the annual per capita out-of-pocket expenses for health
Talja [164]

Answer:

During the year 2021.

Step-by-step explanation:

As we have a function that defines the annual per capita out-of-pocket expenses for health care, we can work with it.

Knowing that, <u>we clear x</u> (<em>this is the number of years past the year 2000, so it will contain our desired information</em>).

y=39.6x+543\Leftrightarrow x=\frac{y-543}{39.6}

Now, as we want to know when are the per capita out-of-pocket expenses for health care predicted to be $1400, and <em>this total is our variable y</em>, then

x=\frac{1400-543}{39.6}\approx 21.6

Finally, we know that <u>x is the number of years past the year 2000</u>, so the answer is that during the year 2021, <em>the per capita out-of-pocket expenses for health care are predicted to be $1400</em>.

3 0
3 years ago
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