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OLga [1]
2 years ago
11

Given: E is the midpoint of and ABCD is a rectangle. Prove: △ABE≅△DCE.

Mathematics
1 answer:
andrezito [222]2 years ago
6 0

Answer:

AE = ED/////  A MIDPOINT DIVIDES A SEGMENT INTO TWO CONGRUENT SEGMENTS

AB = DC ///// OPPOSITE SIDES OF A RECTANGLE ARE CONGRUENT

<A IS A RIGHT ANGLE ///// THE INTERIOR ANGLES OF A RECTANGLE ARE RIGHT ANGLES

<D IS A RIGHT ANGLE ///// THE INTERIOR ANGLES OF A RECTANGLE ARE RIGHT ANGLES

<A = <D ///// ALL RIGHT ANGLES ARE CONGRUENT

TRIANGLES ABE = DCE ///// SAS

Hope this might help you.

Step-by-step explanation:

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Step-by-step explanation:

Given:

Pedro building a playground in shape of right angled triangle.

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How much sand he need to buy

And if playground changed to rectangle what will be the dimensions.

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<em>Consider a ΔABC be the play ground vertex of playground,</em>

<em>And AB and BC be the sides making right angle.</em>

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(Refer the attachment)

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