We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
B
Step-by-step explanation:
If you plug in 5 1/3 to the equation, the result is 6, meaning that the point lies on the line.
Hey!
Your answer is solved below/above idk wherever just see in the picture.
1. To answer the questions shown in the figure atttached, it is important to remember that the irrational number e is aldo called "Euler's number" and you can find it in many exercises in mathematics.
2. Then, the irrational number e is:
e=<span>2.71828
</span>
3. When you rounded, you have:
e=<span>2.718
</span>
4. Therefore, as you can see, the the correct answer for the exercise above is the option c, which is: c. 2.718
