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Dmitrij [34]
3 years ago
14

A cyclist rode for 3.5 hours and completed a distance of 60.9 miles. If she kept the same average speed for each hour, how far d

id she ride in 1 hour? Part B Find the exact distance she rode in 1 hour by completing the division.
Mathematics
2 answers:
asambeis [7]3 years ago
8 0

Answer:

A cyclist rode distance of 17.4 miles of distance in 1 hour,.

Step-by-step explanation:

Distance covered by cyclist = d = 60.9 miles

Time taken to cover d distance = t = 3.5 hours

Speed of the cyclist = s

Speed=\frac{Distance}{Time}

s=\frac{d}{t}=\frac{60.9 mile}{3.5 hour}=17.4 mile/hour

A cyclist rode distance of 17.4 miles of distance in 1 hour,.

SVETLANKA909090 [29]3 years ago
5 0

divide total miles by total time:

60.9 / 3.5 = 17.4 miles per hour

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Determine the length of GH. Round to the nearest tenth.<br> 3.9 cm<br> G<br> 52<br> 642<br> H
sesenic [268]

Answer:

|GH| = 5,7 cm

Step-by-step explanation:

To know |GH|, you first need to find the length of |GD|.

We can calculate |GD| by;

cosG = |GC| / |GD|

<=> |GD| = |GC| / cosG

 => |GD| = 3,9 cm/ 0,62 = 6,33 cm

We now can easily calculate |GH| with the sinus of angle D;

sinD = |GH| / |GD|

<=> |GH| = sinD.|GD|

 => |GH| = 0,899.6,33 cm = 5,694 cm => 5,7 cm

I hope i did not make a mistake ...

5 0
3 years ago
A rectangular school banner has a length of 44 inches, a perimeter of 156 inches, and an area of 1,496 square inches. the cheerl
STatiana [176]

A rectangular school banner has a length of 44 inches, a perimeter of 156 inches, and an area of 1,496 square inches. the cheerleaders make signs similar to the banner. the length of a sign is 11 inches. First solve the width of the rectangle:

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So the sign has also a width of 34 in and a length of 11 so the area is 34*11 =374 sq in

<span>The perimeter is (34*2) +(11*2) =90 in</span>

3 0
3 years ago
Anyone know how to do trig? Given tan Ф = 4/5, find all other trig functions.
mars1129 [50]

9514 1404 393

Answer:

  • sin(Ф) = (4/41)√41; csc(Ф) = (√41)/4
  • cos(Ф) = (5/41)√41; sec(Ф) = (√41)/5
  • tan(Ф) = 4/5; cot(Ф) = 5/4

Step-by-step explanation:

The mnemonic SOH CAH TOA can help you with three of the functions. Then you need to remember the relations between those and the other three.

  Tan = Opposite/Adjacent

  tan(Ф) = 4/5

This suggests you can draw a triangle like the one attached that has adjacent side 5 and opposite side 4. Then hypotenuse can be found from the Pythagorean theorem:

  AC² = AB² +BC² = 5² +4² = 41

  AC = √41 . . . . . hypotenuse

Then the other trig functions are ...

  Sin = Opposite/Hypotenuse

  sin(Ф) = 4/√41 = (4/41)√41

  Cos = Adjacent/Hypotenuse

  cos(Ф) = 5/√41 = (5/41)√41

And the reciprocal functions are ...

  csc(Ф) = 1/sin(Ф) = (√41)/4

  sec(Ф) = 1/cos(Ф) = (√41)/5

  cot(Ф) = 1/tan(Ф) = 5/4

7 0
3 years ago
What is a common factor?
dybincka [34]
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</span>Example: 12 and 30
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</span>
-Hope this helped.
7 0
3 years ago
***Please Help As Soon As Possible***
Nastasia [14]
Hey, ok so 1) is A  
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5 0
3 years ago
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