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3 years ago

suppose the expression was (12-3) to the second power would you have to still simplify 3 to the second power first explain

1 answer:

4 0

You would take which ever number is taken to the power sat it was 12 to the power of 2+4, you would take the 12 not the 4, Hope this helps!

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The fair market rental rate for Bloomington is $747 and for Kokomo is $654. The relative change from Bloomington to Kokomo is __

irina1246 [14]

Answer:

<em>The relative change from Bloomington to Kokomo is -12.449...%</em>

Step-by-step explanation:

The fair market rental rate for Bloomington is $747 and for Kokomo is $654.

So, the amount of relative change from Bloomington to Kokomo will be: $(\$654-\$747)=-93$ dollar.

<em>Formula for percentage of relative change = (Amount of relative change/ Initial amount)× 100%</em>

So, the percentage will be: $\frac{-93}{747}\times 100\% =-12.449.... \%$

5 0

3 years ago

y = 2x squared + 5x -3 can be written in the form y= 2( x+a) squared + b . Find the value of a and the value of b.

Elan Coil [88]

General vertex form:

$y = m(x − a)² + b \: with \: vertex \: at \: (a, b)$

Given :

$y = 2x² + 5x - 3$

Extract "spread factor" m

$y = 2( x² + \frac{5}{2} x) - 3$

Complete the square

$y = 2(x² + \frac{5}{2}x + ( \frac{5}{4})²) - 3$

$- 2( \frac{5}{4})²$

Write as a squared binomial and simplify the constant

$y = 2(x + \frac{5}{4})² - 6 \frac{1}{8}$

Re-write to match signs of standard general form:

$y = 2(x - ( - \frac{5}{4}))² \: + ( - 6 \frac{1}{8})$

3 0

3 years ago

PLEEZZ

jonny [76]

4 < 4(6y - 12) - 2y |use distributive property

4 < (4)(6y) + (4)(-12) - 2y

4 < 24y - 48 - 2y |add 48 to both sides

52 < 26y |divide both sides by 26

2 < y → y > 2

---------------------------------------------------------

4x + 3 < 3x + 6 |subtract 3 from both sides

4x < 3x + 3 |subtract 3x from both sides

x < 3

------------------------------------------------------------

-5r + 6 ≤ -5(r + 2) |use distributive property

-5r + 6 ≤ (-5)(r) + (-5)(2)

-5r + 6 ≤ -5r - 10 |add 5r to both sides

6 ≤ -10 FALSE

No solution

-------------------------------------------------------------

-2(6 + s) ≥ -15 - 2s |use distributive property

(-2)(6) + (-2)(s) ≥ -15 - 2s

-12 - 2s ≥ -15 - 2s |add 2s to both sides

-12 ≥ -15 TRUE

All real numbers

-------------------------------------------------------------

3s + 6 ≤ -5(s + 2) |use distributive property

3s + 6 ≤ (-5)(s) + (-5)(2)

3s + 6 ≤ -5s - 10 |subtract 6 from both sides

3s ≤ -5s - 16 |add 5s to both sides

8s ≤ -16 |divide both sides by 8

s ≤ -2

--------------------------------------------------------------

4/3 s - 3 ?

4 0

3 years ago

What's the result of 240 increased by 5%

garri49 [273]

252 is the answer for your question

3 0

3 years ago

Read 2 more answers

Your friend says that the absolute value equation |3x+8|−9=−5 has no solution because the constant on the right side of the equa

xenn [34]

$Solution, solve\:for\:x,\:\left|3x+8\right|-9=-5\quad :\quad x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$Steps:$

$\left|3x+8\right|-9=-5$

$\mathrm{Add\:}9\mathrm{\:to\:both\:sides},\\\left|3x+8\right|-9+9=-5+9$

$\mathrm{Simplify},\\\left|3x+8\right|=4$

$|f\left(x\right)|=a\quad \Rightarrow \:f\left(x\right)=-a\quad \mathrm{or}\quad \:f\left(x\right)=a,\\3x+8=-4\quad \quad \mathrm{or}\quad \:\quad \:3x+8=4$

$3x+8=-4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=-4-8,\\\mathrm{Simplify},\\3x=-12,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-12}{3},\\\mathrm{Simplify},\\x=-4$

$3x+8=4,\\\mathrm{Subtract\:}8\mathrm{\:from\:both\:sides},\\3x+8-8=4-8,\\\mathrm{Simplify},\\3x=-4,\\\mathrm{Divide\:both\:sides\:by\:}3,\\\frac{3x}{3}=\frac{-4}{3},\\\mathrm{Simplify},\\x=-\frac{4}{3}$

$Combine\:the\:ranges,\\x=-4\quad \mathrm{or}\quad \:x=-\frac{4}{3}$

$\mathrm{The\:Correct\:Answer\:is\:No\:They\:Are\:Not\:Correct}$

$\mathrm{Hope\:This\:Helps!!!}$

$\mathrm{-Austint1414}$

4 0

3 years ago