If 'a' is a rational number and c is rational, then
a = p/q
c = r/s
where p,q,r,s are integers (q and s can't be zero)
Subtracting c-a gives
b = c-a
b = (p/q) - (r/s)
b = (ps/qs) - (qr/qs)
b = (ps - qr)/(qs)
The quantity pq - qr is an integer. The reason why is because ps and qr are both integers (multiplying any two integers leads to another integer). Subtracting any two integers results in another integer.
So we have (ps - qr)/(qs) in the form (integer)/(integer) = rational number
Therefore, b is a rational number, but this contradicts the given info that b is irrational. If b is irrational, then we CANNOT write it as a ratio of integers.
This contradiction proves the assumption "a+b = c and c is rational" is incorrect
The sum is irrational.
Therefore, if a+b = c, where 'a' is rational and b is irrational, then c is irrational.
papi frio
Step-by-step explanation:
Answer:
4950
Step-by-step explanation:
you round down from the 50
Step-by-step explanation:
20+12+90+20
40+12+90
142
180-142
38
I think it is 38
But i don't understand is round to nearest angle tho sorry