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tatyana61 [14]
4 years ago
10

How do I solve for Y 6-3y=-6

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

6-3y=-6

Move 6 to the other side

Sign changes from +6 to -6

6-6-3y= -6-6

-3y= -6-6

-3y= -12

divide both sides by -3

-3y/-3= -12/-3

Answer: y= 4

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Which graph of y=log(-x)?
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7 0
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The variable Z is directly proportional to X. When X is 6, Z has the value 18.
Reika [66]

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7 0
3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
3 years ago
Hi does anyone know how to solve this question if so please show the working out.
tester [92]

Explanation:

The Law of Sines is your friend, as is the Pythagorean theorem.

Label the unmarked slanted segments "a" and "b" with "b" being the hypotenuse of the right triangle, and "a" being the common segment between the 45° and 60° angles.

Then we have from the Pythagorean theorem ...

  b² = 4² +(2√2)² = 24

  b = √24

From the Law of Sines, we know that ...

  b/sin(60°) = a/sin(θ)

  y/sin(45°) = a/sin(φ)

Solving the first of these equations for "a" and the second for "y", we get ...

  a = b·sin(θ)/sin(60°)

and ...

  y = a·sin(45°)/sin(φ)

Substituting for "a" into the second equation, we get ...

  y = b·sin(θ)/sin(60°)·sin(45°)/sin(φ) = (b·sin(45°)/sin(60°))·sin(θ)/sin(φ)

So, we need to find the value of the coefficient ...

  b·sin(45°)/sin(60°) = (√24·(√2)/2)/((√3)/2)

  = √(24·2/3) = √16 = 4

and that completes the development:

  y = 4·sin(θ)/sin(φ)

6 0
3 years ago
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