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tatyana61 [14]
4 years ago
10

How do I solve for Y 6-3y=-6

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

6-3y=-6

Move 6 to the other side

Sign changes from +6 to -6

6-6-3y= -6-6

-3y= -6-6

-3y= -12

divide both sides by -3

-3y/-3= -12/-3

Answer: y= 4

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How many different three-digit numbers can be written using digits from the set 5, 6, 7, 8, 9 without any repeating digits?
suter [353]

Answer: 60 different numbers can be formed

Step-by-step explanation:

Note that we have 5 different digits, and we must select 3 of them. They should not be repeated

The order of selection is important in this case, because the number 532 is not the same as the number 235.

So we have a permutations problem, where we have a set of n elements and we want to choose r from them.

Then we define the permutacion as:

nPr=\frac{n!}{(n-r)!}

In this case note that n=5 because there are 5 elements in the set.

r = 3 because we combine the elements to form three-digit numbers

Then:

5P2=\frac{5!}{(5-3)!}

5P2=\frac{5!}{2!}

5P2=\frac{5*4*3*2!}{2!}

5P2=5*4*3

5P2=60

4 0
3 years ago
Which of the following equations is of a parabola with a vertex at (1,2)
labwork [276]

ANSWER

The choice is correct.

y = {(x -1)}^{2}  + 2

EXPLANATION

The equation of a parabola in vertex form is given by:

y = a {(x -h)}^{2}  + k

where (h,k) is vertex of the parabola and 'a' is the leading coefficient of the parabola.

From the given options, the leading coefficient must be a=1.

We also have the vertex of the parabola at (1,2). This implies that h=1 and k=2.

We substitute these values into the formula to get,

y = {(x -1)}^{2}  + 2

The second option is correct.

4 0
3 years ago
Fine the next three terms in each geometric sequence<br> 2,-10,50,...
lakkis [162]

Answer:

2, -10, 50, -250, 1250, -6250

Step-by-step explanation:

its times -5 every time

4 0
3 years ago
Simplify ratio 12:28:20
Tamiku [17]

Answer:

3 : 7 : 5

Step-by-step explanation:

Given

12 : 28 : 20 ← divide each part by 4 ( the LCM of 12, 28, 20 )

= 3 : 7 : 5

5 0
3 years ago
What are the x-coordinates for the maximum points in the function f(x)=4cos(2x-pi) from x=0 to x=2pi
prisoha [69]
The answer to the problem is as follows:

<span>Well isn't the range of y=cos(u) is [-1,1]

So the max value for y=cos(u) is 1
 
And the min value for y=cos(u) is -1 --

So the max value for f(x)=4cos(u) is:
</span>
<span>f(u)=4cos(u)
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
8 0
4 years ago
Read 2 more answers
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