Answer:
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Step-by-step explanation:
A distribution is called uniform if each outcome has the same probability of happening.
The uniform distributon has two bounds, a and b, and the probability of finding a value between c and d is given by:
The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.
This means that 
If one such class is randomly selected, find the probability that the class length is between 51.5 and 51.7 min.
0.1 = 10% probability that the class length is between 51.5 and 51.7 min, that is, P(51.5 < X < 51.7) = 0.1.
Don't get confused by the "0.01 cm" that's just telling you to round to the hundredths place. Moving on, the shaded area's exterior shows us that it is a square. Meaning you do s^2 to find the area. So, you find the square root of 15 which is <span>3.87... This means the diameter is also 3.87 because the diameter is equivalent to the side's measurement. Divide 3.87 by 2 to find the radius, giving you 1.935. This represents OT's length. Now, just round to the hundredths giving you 1.94 cm. </span>
Hey there mate!
Please check the attached answer of picture for explanation.
Length of each side of each of these three equilateral triangle is :
Solution is in attachment ~
Answer:
Step-by-step explanation:
Hello,
We need to express this parabola using this kind of expression
and then, the line of symmetry will be the line x = b
Let's do it !
![\text{*** Complete the square ***} \\ \\ x^2+x=x+2\cdot \dfrac{1}{2}\cdot x=(x+\dfrac{1}{2})^2-\dfrac{1^2}{2^2}=(x+\dfrac{1}{2})^2-\dfrac{1^2}{4} \\ \\ \text{*** Apply it to our parabola } \\ \\y=-x^2-x+2=-(x^2+x)+2=-[(x+\dfrac{1}{2})^2-\dfrac{1}{4}]+2 = -(x+\dfrac{1}{2})^2+\dfrac{1+2*4}{4}= -(x+\dfrac{1}{2})^2+\dfrac{9}{4} \\ \\ \text{*** It comes ***} \\ \\ \Large \boxed{\sf \ \ y=-(x+\dfrac{1}{2})^2+\dfrac{9}{4} \ \ }](https://tex.z-dn.net/?f=%5Ctext%7B%2A%2A%2A%20Complete%20the%20square%20%2A%2A%2A%7D%20%5C%5C%20%5C%5C%20x%5E2%2Bx%3Dx%2B2%5Ccdot%20%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%20x%3D%28x%2B%5Cdfrac%7B1%7D%7B2%7D%29%5E2-%5Cdfrac%7B1%5E2%7D%7B2%5E2%7D%3D%28x%2B%5Cdfrac%7B1%7D%7B2%7D%29%5E2-%5Cdfrac%7B1%5E2%7D%7B4%7D%20%5C%5C%20%5C%5C%20%5Ctext%7B%2A%2A%2A%20Apply%20it%20to%20our%20parabola%20%7D%20%5C%5C%20%5C%5Cy%3D-x%5E2-x%2B2%3D-%28x%5E2%2Bx%29%2B2%3D-%5B%28x%2B%5Cdfrac%7B1%7D%7B2%7D%29%5E2-%5Cdfrac%7B1%7D%7B4%7D%5D%2B2%20%3D%20-%28x%2B%5Cdfrac%7B1%7D%7B2%7D%29%5E2%2B%5Cdfrac%7B1%2B2%2A4%7D%7B4%7D%3D%20-%28x%2B%5Cdfrac%7B1%7D%7B2%7D%29%5E2%2B%5Cdfrac%7B9%7D%7B4%7D%20%5C%5C%20%5C%5C%20%5Ctext%7B%2A%2A%2A%20It%20comes%20%2A%2A%2A%7D%20%5C%5C%20%5C%5C%20%5CLarge%20%5Cboxed%7B%5Csf%20%5C%20%5C%20y%3D-%28x%2B%5Cdfrac%7B1%7D%7B2%7D%29%5E2%2B%5Cdfrac%7B9%7D%7B4%7D%20%5C%20%5C%20%7D)
So the line of symmetry is
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
