The proof is given below.
Step-by-step explanation:
Given,
AB║DC and AB≅DC
To proof ΔABE ≅ Δ CDE
Proof:
AB║DC and AC is the transversal
∠BAE = ∠ECD ( alternate angle)
AB║DC and BD is the transversal
∠ABE = ∠EDC( alternate angle)
Now,
In ΔABE and Δ CDE
∠BAE = ∠ECD ( alternate angle)
∠ABE = ∠EDC( alternate angle)
∠AEB = ∠CED (vertically opposite angle)
So, by AAA condition we get,
ΔABE ≅ Δ CDE
