Answer:
True, see proof below.
Step-by-step explanation:
Remember two theorems about continuity:
- If f is differentiable at the point p, then f is continuous at p. This also applies to intervals instead of points.
- (Bolzano) If f is continuous in an interval [a,b] and there exists x,y∈[a,b] such that f(x)<0<f(y), then there exists some c∈[a,b] such that f(c)=0.
If f is differentiable in [0,4], then f is continuous in [0,4] (by 1). Now, f(0)=-1<0 and f(4)=3>0. Thus, we have the inequality f(0)<0<f(4). By Bolzano's theorem, there exists some c∈[0,4] such that f(c)=0.
I think the answer is B but not sure about "11" in A
2/5 = x/10
2/5 x 2 = 4/10
x= 4
2/5 = 4/10
There are a lot of ways you can do this, depending on what numbers you use, you can divide, multiply, add, or subtract to get 4,384, did you mean a specific term of math?<span />
It’s b
it has to be 20 c long … kskdhdhiIakakkwdydyxiajajshsuuaisudj
