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pantera1 [17]
3 years ago
15

Can somebody help and show there work I don’t understand this PERIOD. I need help ASAP

Mathematics
2 answers:
iren2701 [21]3 years ago
8 0
In general to be able to add or subtract fractions you need to have the same denominator so that you can add the numerators.

The easiest way to find the same denominator is to identify the lowest common denominator (LCD).

You can find the LCD by finding the prime factors of the denominators in question and multiplying them all together. If the denominators share a prime factor, only multiply it once.

Sometimes you can just eyeball the numbers to find the LCD, which might be faster.

For #W we need to find the LCD of 10 and 6, so prime factorize:

10 = 2 x 5
6 = 2 x 3

LCD = 2 x 5 x 3 = 30

The LCD is 30, so we need to change the fraction to reflect that. Remember, what you do to the denominator you need to do to the numerator as well. So:

-9/10 becomes -27/30 (both multiplied by 3)
-1/6 becomes -5/30 (both multiples by 5)

Now you can easily add:

-27/30 + (-5/30) = -32/30

In summary:
Step #1: find LCD (prime factor or eyeball)
Step #2: multiply the numerator of each fraction by the factor needed to obtain the LCD in that denominator
Step #3: add the fractions now that they have the LCD

Here’s the solution to #G:

-¾ + (-7/12)

Step #1:

4 = 2 x 2
12 = 2 x 2 x 3

LCD = 2 x 2 x 3 (count each unique prime factor once)

Step #2:

-¾ becomes -9/12 (both multiplied by 3)
-7/12 stays the same (it already has the LCD)

Step #3:

-9/12 + (-7/12) = -16/12

Let me know if you have any questions. Try to work though the others!
oksano4ka [1.4K]3 years ago
8 0
The explanation for how to solve all of them is shown through the example on the paper. I solved W, the first one, to show you how to solve all of the rest of the problems. Let me know if you have any questions about the work! Hope this helps :)

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Please show me how you got the answer. Will give brainliest.
umka21 [38]

Answer:          410 possible points

To solve for the possible points in the course, use a proportion and cross multiply.

<h2>What is a proportion?</h2>

A proportion is two fractions that are equal to each other. For the fractions to be equal, they are proportionate. In our math problem, percentage is proportionate the the number of points.

The fractions represent information you have, and one variable will represent what you are solving for.

<h2 /><h3>Given</h3>

Your points = 361

Points to get an 'A' = your points + 8

'A' = 90% of possible points

<h3>Find the points needed for an 'A' at 90%</h3>

Points to get an 'A' = your points + 8

= 361 + 8

= 369

<h3>State variables</h3>

let <em>x</em> be the amount of possible points

<h3 /><h3>Write a proportion</h3>

We know the number of points for 90% is 369 points. Remember that 90% is the same as 90/100.

Keep the information with the same units inside the same fraction. Here, percentage is represented by the first fraction. Points is represented by the second fraction.

\displaystyle{\frac{90}{100}=\frac{369}{x}}

<h3>Solve</h3>

We can solve using cross multiplication. This is when we multiply each numerator by the denominator from the other fraction.

90x = 369*100        Simplify by multiplying.

90x = 36,900            Isolate the variable <em>x</em>.

\displaystyle{\frac{90x}{90} = \frac{36,900}{90}}           Divide both sides by 90 to cancel out 90 on the left.

\displaystyle{x = \frac{36,900}{90}}              Divide.

x = 410                    Solved for <em>x</em>, representing the possible points.

∴ The possible points in the art course is 410.

Learn more about finding a missing number given percentage here: brainly.com/question/26535441

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1 year ago
Please help me its help.
IgorLugansk [536]

The answer will be 81.

Step-by-step explanation:

just multiple by 3

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Answer:

Step-by-step explanation:

1. A + B

2. 9 + u - 10

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#1. What term describes a line segment that connects a vertex of a triangle to a point on the line containing the opposite side,
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The ALTITUDE is a line segment that connects a vertex of a triangle to a point on the line containing the opposite side, so that the line segment is perpendicular to that line.

#2
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