Upon a slight rearrangement this problem gets a lot simpler to see.

x^3-x+2x^2-2=0 now factor 1st and 2nd pair of terms...

x(x^2-1)+2(x^2-1)=0

(x+2)(x^2-1)=0 now the second factor is a "difference of square" of the form:

(a^2-b^2) which always factors to (a+b)(a-b), in this case:

(x+2)(x+1)(x-1)=0

So g(x) has three real zero when x={-2, -1, 1}

4 0

2 years ago

The average number of accidents is 3 per month, what is the probability of 1 accident?

tatuchka [14]

<h2>Hello!</h2>

The answer is: 33.33%

Since we have the average number of accidents that occurs in 1 month, and it's equal to 3, we can calculate the probability of 1 accident occurs by dividing it into the average number of accidents, using the following formula:

$Probability=\frac{FavorableOutcomes}{Outcomes}*100$

Where,

Favorable outcomes are the occurrence of the event, for this case, it's equal to 1.

Outcomes are the possible occurrence of the event, for this case, it's equal to 3.

So, by substituting we have:

$Probability=\frac{1}{3}*100$

$Probability=0.3333*100=33.33$

So, the probability will be equal to 33.33%

Have a nice day!

7 0

3 years ago