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Tanya [424]
3 years ago
13

If on the unit circle C, the distance from P(1, 0) to the point T ( 4/5 , 3/5 ) is x, determine the coordinates of the point at

the indicated distance: P - x
(4/5, 3/5)
(-4/5, 3/5)
(4/5, -3/5)
(-4/5, -3/5)​

Mathematics
1 answer:
AveGali [126]3 years ago
3 0

Answer:

(\frac{4}{5}, -\frac{3}{5}  )

Step-by-step explanation:

The point P(1,0) and T(\frac{4}{5}, \frac{3}{5}  ) are on the unit circle C and the arc length from P to T is x.

Let us assume that point P - x i.e. the point obtained by moving clock wise direction along the circle from P is T'.

Because of the symmetry of the circle about the coordinate axes, the x-coordinate of point T' will be \frac{4}{5} and the y-coordinate will be -\frac{3}{5}.

So, coordinates of T' are (\frac{4}{5}, -\frac{3}{5}  ).

Here we must notice that point T' is the reflection point of T with respect to X-axis. (Answer)

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Romashka [77]

Answer:

The answer is x = 5.

Step-by-step explanation:

Given:

Δ ABC is an Isosceles triangle with AB = CA

   m∠ ABC = ( 6x + 4 )°

   m∠ BAC = 73°

   m∠ BCA = ( 8y - 7 )°

To Find:

x = ?

Solution:

Properties of an Isosceles Triangle.

  1. Base angles or two angles are equal.
  2. Any two sides are equal.

Here , Δ ABC is an Isosceles triangle with AB = CA

∴  m∠ BAC = m∠ BCA

73= 8y-7\\8y=73+7\\8y=80\\y=\frac{80}{10} \\y=10

∴      m∠ BCA = ( 8y - 7 )°

                       = 8 × 10 - 7

       m∠ BCA  = 73  Which is same as ∠ CAB

Property of a Triangle is Sum of the measures of the angle of a triangle is 180°.

\angle ACB + \angle CAB + \angle CBA = 180

Substituting the values we get,

73 + 73 + (6x+4) = 180\\6x+4=180-146\\6x=34-4\\6x=30\\x=\frac{30}{6} \\x=5\\

The answer is x = 5.

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