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3 years ago

Solve 2x - 8 < 7.

Mathematics

1 answer:

professor190 [17]3 years ago

7 0

Answer:

Step-by-step explanation:

2x - 8 < 7 <em>add 8 to both sides</em>

2x - 8 + 8 < 7 + 8

2x < 15 <em>divide both sides by 2</em>

2x : 2 < 15 : 2

x < 15/2

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Answer: $A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]$

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$\left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]$

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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For BC a diagonal, D3 is ...

B+C-A = (1+2-(-2), 1-2-2) = (5, -3)

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3 years ago

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