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sammy [17]
3 years ago
7

What is 7/8 as a percentage?

Mathematics
2 answers:
nydimaria [60]3 years ago
8 0

7/8 As A Percentage Is 87.5%

To find what 7/8 as a percentage is, first we have to divide 7 by 8 which we get a quotient of 0.875.

Then we multiply 0.875 by 100 to get 87.5%

Have A Great Day!

julia-pushkina [17]3 years ago
3 0

Answer:

87.5%

Step-by-step explanation:

7/8x100=87.5

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Y + 2.13 = -9.74 I need help
Oduvanchick [21]
To get y alone you would subtract 2.12 so
Y = -11.87
7 0
3 years ago
Which rule describes the translation? t–3, –2(x, y) t–3, 2(x, y) t3, –2(x, y) t3, 2(x, y)
denis23 [38]

The rule that describes the translation is T3, -2 (x,y)

<h3>How to determine the translation rule?</h3>

The graph that completes the question is added as an attachment

From the attached graph, we have the following highlights:

  • Quadrilateral ABCD is translated 3 units right
  • Quadrilateral ABCD is translated 2 units down

This is represented as:

T3, -2 (x,y)

Hence, the rule that describes the translation is T3, -2 (x,y)

Read more about translation at:

brainly.com/question/8914076

#SPJ1

5 0
2 years ago
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Solve <img src="https://tex.z-dn.net/?f=%5Cfrac%7B6x%2B7%7D%7B5%7D%20%3D2x-4" id="TexFormula1" title="\frac{6x+7}{5} =2x-4" alt=
Helen [10]
Answer: x=27/4 hope it helps
4 0
3 years ago
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Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side
lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

       =cot x (sec²x)²

       =cot x (1+tan²x)²     [ ∵ sec²x=1+tan²x]

       =  cot x(1+ 2 tan²x +tan⁴x)

       =cot x+ 2 cot x tan²x+cot x tan⁴x

        =cot x +2 tan x + tan³x        [ ∵cot x tan x =\frac{ \textrm{tan x }}{\textrm{tan x}} =1]

       =R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

 L.H.S =(sin x)(tan x cos x - cot x cos x)

          = sin x tan x cos x - sin x cot x cos x

           =\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}

           = sin²x -cos²x

           =1-cos²x-cos²x

           =1-2 cos²x

           =R.H.S

         

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

         =1+\frac{{sin^2x}}{cos^2x}                       [\textrm{sec x}=\frac{1}{\textrm{cos x}}]

         =1+tan²x                        [\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]

         =sec²x

        =R.H.S

4.

\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}

L.H.S=\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}

       =\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}

      =\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}

     =\frac{\textrm{2sin x}}{sin^2 x}

      = 2 csc x

    = R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

        = sec²x-tan²x

        =\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}

        =\frac{1- sin^2x}{cos^2x}

        =\frac{cos^2x}{cos^2x}

        =1

     

       

8 0
4 years ago
Factorization of <br>x²+6x+5​
crimeas [40]

Answer:

(x +1) (x + 5)

Step-by-step explanation:

Factorization of x²+6x+5​

To factorise this quadratic expression we'll find 2  factors of 5 that when added gives the coefficient of x which is

Factors = +1 and +5

Sum = +6, product = +5

Rewriting equation

x² + x + 5x + 5

Factorising

x ( x +1) +5 ( x + 1)

(x +1) (x + 5)

I hope this was helpful, please mark as brainliest

7 0
3 years ago
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