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sveta [45]
3 years ago
9

A. 1 and 8 B. 4 and 6 C. 5 and 6 D. 1 and 7 Please tell me why

Mathematics
1 answer:
andre [41]3 years ago
6 0
1 and 7 because they have the same angles

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Please Help Me On This
anastassius [24]

Answer:

X2 = (-2, 1), W2 = (-4, 1), Y2 = (4, -2), Z2 = (-3, 2)

Step-by-step explanation:

First, flip across the y-axis:

Coordinates: X1 = (2, -1), W1 = (4, -1), Y1 = (2, -4), and Z1 = (3, -2)

Then, rotate 180 degrees counterclockwise:

Coordinates: See above

5 0
3 years ago
Graph f(x)= 1/x-2 include asymptotes, at least 5 points, and neatly sketch the branches
riadik2000 [5.3K]

Answer:

I attached the answer below.

Step-by-step explanation:

I recommend using Desmos, that's what I used. It helps graph and plot points.

Hope this helps!!

7 0
2 years ago
Are the following expressions equivalent 26-(-26) and 26+(-26)
kotegsom [21]

Answer:

No.

Step-by-step explanation:

They are not because the left side is 52, while the right side is 0.

5 0
3 years ago
PLZ HELP!!! Use limits to evaluate the integral.
Marrrta [24]

Split up the interval [0, 2] into <em>n</em> equally spaced subintervals:

\left[0,\dfrac2n\right],\left[\dfrac2n,\dfrac4n\right],\left[\dfrac4n,\dfrac6n\right],\ldots,\left[\dfrac{2(n-1)}n,2\right]

Let's use the right endpoints as our sampling points; they are given by the arithmetic sequence,

r_i=\dfrac{2i}n

where 1\le i\le n. Each interval has length \Delta x_i=\frac{2-0}n=\frac2n.

At these sampling points, the function takes on values of

f(r_i)=7{r_i}^3=7\left(\dfrac{2i}n\right)^3=\dfrac{56i^3}{n^3}

We approximate the integral with the Riemann sum:

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{112}n\sum_{i=1}^ni^3

Recall that

\displaystyle\sum_{i=1}^ni^3=\frac{n^2(n+1)^2}4

so that the sum reduces to

\displaystyle\sum_{i=1}^nf(r_i)\Delta x_i=\frac{28n^2(n+1)^2}{n^4}

Take the limit as <em>n</em> approaches infinity, and the Riemann sum converges to the value of the integral:

\displaystyle\int_0^27x^3\,\mathrm dx=\lim_{n\to\infty}\frac{28n^2(n+1)^2}{n^4}=\boxed{28}

Just to check:

\displaystyle\int_0^27x^3\,\mathrm dx=\frac{7x^4}4\bigg|_0^2=\frac{7\cdot2^4}4=28

4 0
3 years ago
What is the value of (14)5?
valina [46]

Answer:

70

Step-by-step explanation:

7 0
2 years ago
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