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madreJ [45]
3 years ago
13

In 3-8, find the missing side length of each right triangle. 50yd. 30yd.

Mathematics
1 answer:
denis23 [38]3 years ago
7 0
Hi! so you didn’t let us know which side length is missing and it kind of matters so i’ll attach an image so you can just copy the one that looks most like yours.

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Alex tried to find the lateral area of the pyramid. FIND HIS ERROR AND CORRECT IT.
sweet-ann [11.9K]

Answer:

His error is multiplying by 4 sides as he thought it was total surface not lateral surface area- the final answer is 12

Step-by-step explanation:

He should have multiplied it by 3, because the 3 sides- not including the base- is what lateral surface area is. He originally did total surface area not lateral surface area so each sides area is 4m squared then you just multiply it by 3 and its 12

5 0
3 years ago
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PLZ HELP HELP PLZZ 5/5 × 2 and 3/4 will be greater than less than or equal to 2 and 3/4??​
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1)2
2) less than
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nelson used 35% of his savings account for his class trip in May. if he used $140 from his savings account while on his class tr
Liono4ka [1.6K]

Answer:

He had 189 dollars

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35% of 140 is 49

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3 years ago
4 to the seventh power over 5 squared all raised to the third power
Komok [63]

(4^7 / 5^2)^3

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3 years ago
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Can somebody number the problem and work it out for me thanks and btw it’s solving system by graphics
adoni [48]

Answer:

Solutions are (3,1) and (4,2)

Step-by-step explanation:

Graph is shown in the attached sheet

Given are two systems of equations and we have to solve them using graph

For graphing let us first prepare table for x and y.

1) y=\frac{-2x}{3} +3:\\y=2x-5

I line                                                             II line

x     0   4.5    3                              x       0      2.5     3

y      3   0       1                              y       -5      0        1

The two lines intersect at (3,1)

Hence solution is (3,1)

--------------------------------------------

2) y=\frac{x}{2} \\-6x+3y=-18

I line                                                             II line

x     0    2    4                              x       0      6     4

y      0   1      2                             y       3      0     2

The two lines intersect at (4,2)

Hence solution is (4,2)

3 0
3 years ago
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