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madreJ [45]
3 years ago
13

In 3-8, find the missing side length of each right triangle. 50yd. 30yd.

Mathematics
1 answer:
denis23 [38]3 years ago
7 0
Hi! so you didn’t let us know which side length is missing and it kind of matters so i’ll attach an image so you can just copy the one that looks most like yours.

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Odette made this jewelry box by combining two rectangular boxes.
Komok [63]
382in^2

Adding the sides up we get, 36+36+72+24+24+24+32+48+48+48
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fankssss

Step-by-step explanation:

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3 years ago
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Si 9/11, 5/m+3, 15/N-7, 18/p-1 son fracciones homogeneas como calculo m+n+p
notsponge [240]
I’m confused, can you explain
5 0
3 years ago
You bike 1 mile the first day of your​ training, 1.3 miles the second​ day, 1.9 miles the third​ day, and 3.1 miles the fourth d
JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

d_1=1 mi is the distance travelled during the 1st day

d_2=1.3 mi is the distance travelled during the 2nd day

d_3=1.9 mi is the distance travelled during the 3rd day

d_4=3.1 mi is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2

Which can be rewritten using the general formula:

d_{n+1}-d_n=2(d_n-d_{n-1})

This means that

d_{n+1}=d_n+2(d_n-d_{n-1})

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi

So, the  distance travelled on the 7th day is 19.9 miles.

7 0
3 years ago
Use the method of completing the square to solve x2 - 6x + 1 = 0. Simplify your solutions.
exis [7]

Answer:

x = 3 ± 2\sqrt{2}

Step-by-step explanation:

given

x² - 6x + 1 = 0 ( subtract 1 from both sides )

x² - 6x = - 1

To complete the square

add (half the coefficient of the x- term)² to both sides

x² - 6x + (- 3)² = - 1 + (- 3)²

x² - 6x + 9 = - 1 + 9

(x - 3)² = 8 ( take the square root of both sides )

x - 3 = ± \sqrt{8} = ± 2\sqrt{2} ( add 3 to both sides )

x = 3 ± 2\sqrt{2}

8 0
3 years ago
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