Question

Find the derivative y=x(2^x) y’=

Answer 1

Answer:

$y' =2^x ( 1 + xln 2 )$

Step-by-step explanation:

given,

$y= x\ 2^x$

$\frac{\mathrm{d} y}{\mathrm{d} x} = \frac{\mathrm{d} }{\mathrm{d} x}(x\ 2^x )$

using chain rule

$y'= x (2^x ln 2) + 2^x(1)$

$y' = 2^x + x (2^x ln 2)$

$y' =2^x ( 1 + xln 2 )$

hence the answer is given above.