I cant hardly see it ,what's the question?
Answer:
1. $686.94
2. $735.03
3. $10707.55
4. $17631.94
5. $19635.72
Step-by-step explanation:
1st Question:
The interest rate is 7% for each year. This means that each year the person has to pay 7% more than the previous amount. So we need to multiply the initial amount by (0.07+1=1.07) in order to get the interest for the first year. if we want to find the second year's interests then we will have to multiply 2 (1.07)'s and so on.
in this case our function is: 600*(1.07)^t=P(t)
when t=2 P(2)=600*(1.07)^2=$686.94
2nd Question:
Function: 600*(1.07)^t=P(t)
when t=3 P(3)=600*(1.07)^3=$735.03
3rd Question:
initial value=$8500
1+0.08=1.08
Function: 8500*(1.08)^t=P(t)
t=3
P(3)=8500*(1.08)^3=$10707.55
4th Question:
initial value=$12000
1+1.08=1.08
t=5
Function: P(t)=12000*(1.08)^t
P(5)=12000*(1.08)^5=$17631.94
5th Question:
Function: 14000*(1.07)^t=P(t)
P(5)=14000*(1.07)^5
P(5)=$19635.72
Answer:
You can solve this by having 2 different equations and setting both of them to 180 because they are supplemetnary anhles
Step-by-step explanation:
so for abc the equation= 180, then solve
then for the other angle cbd=180, then solve
Answer:
990 ways
Step-by-step explanation:
The total number of automobiles we have is 11.
Now, what this means is that for the first position , we shall be selecting 1 out of 11 automobiles, this can be done in 11 ways( 11C1 = 11!/(11-1)!1! = 11!/10!1! = 11 ways)
For the second position, since we have the first position already, the number of ways we can select the second position is selecting 1 out of available 10 and that can be done in 10 ways(10C1 ways = 10!9!1! = 10 ways)
For the third position, we have 9 automobiles and we want to select 1, this can be done in 9 ways(9C1 ways = 9!/8!1! = 9 ways)
Thus, the total number of ways the first three finishers come in = 11 * 10 * 9 = 990 ways
42 < -6d
divide 6 by both sides,
7 < -d
(C) d > -7 is the answer.
