27 1/5 + 2/6
\\Convert to like fractions:
= 27 6/30 + 10/30
\\Add the fractions
= 27 16/30
\\Simplify by dividing by 2
= 27 8/15
Answer: 27 8/15
Answer:
Yes
Step-by-step explanation:
I've done this before.
Answer:
true
Step-by-step explanation:
first find the median of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.
Answer: 17/7
Step-by-step explanation: Step 1: Simplify both sides of the equation. y+4/15 + 2y−5/5 = 2/5 1/15 y+ 4/15 + 2/5 y+−1= 2/5 (Distribute) ( 1/15 y+ 2/5 y)+( 4/15 +−1)= 2/5 (Combine Like Terms) 7/15 y+ −11/15 = 2/5 7/15 y+ −11/15 = 2/5 Step 2: Add 11/15 to both sides. 7/15 y+ −11/15 + 11/15 = 2/5 + 11/15 7 15 y= 17/15
Answer:
184 cm²
Step-by-step explanation:
Surface area of the rectangular box is expressed as S = 2(LW+LH+WH)
L is the length of the box = 90 cm
W is the width of the box = 50 cm
H is the height of the box= 90 cm
If there are error of at most 0.2 cm in each measurement, then the total surface area using differential estimate will be expressed as shown;
S = 2{(LdW+WdL) + (LdH+HdL) + (WdH+HdW)
Note that dL = dW = dH = 0.2 cm
Substituting the given values into the formula to estimate the maximum error in calculating the surface area of the box
S = 2{(90(0.2)+50(0.2)) + (90(0.2)+90(0.2)) + (50(0.2)+90(0.2))
S = 2{18+10+18+18+10+18}
S = 2(92)
S = 184 cm²
Hence, the maximum error in calculating the surface area of the box is 184cm²
