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cluponka [151]
3 years ago
5

Multiply. write answers in the simplest form: 3 1/4 x 4 2/3

Mathematics
1 answer:
Lorico [155]3 years ago
3 0

13.196969697

yup mhm oh yeah (its not in simplest form sorry)

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It takes alvin 20 weeks, and it takes buzzy 15 weeks
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Write the slope-intercept form of the line that passes through (1, -2) and is parallel to the line y = 4x + 2.
Naily [24]

Use

y-y1=m(x-x1)

y-(-2)=4(x-1) Now why 4??Because parallel lines have the exact same slope

y+2=4x-4

y=4x-4-2

y=4x-6

Hope it helps!

GraceRosalia

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I believe it’s $5.47
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3 years ago
Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En
Sergio [31]

Answer:

\bold{cot(t) =\dfrac{12}{5}}

Step-by-step explanation:

Given that:

Cosec (t) = -\frac{13}5

for \pi < t < \frac{3 \pi}2

That means, angle t is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

cosec^2\theta -cot^2\theta =1

here, \theta =t

So, cosec^2t-cot^2t=1

\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}

But, angle t is in 3rd quadrant, so value of

\bold{cot(t) =\dfrac{12}{5}}

4 0
3 years ago
Which of the following points is a solution of y &gt; Ixl + 5?
Step2247 [10]

Answer:

B. (1,7)

Step-by-step explanation:

We can substitute the x and y values of each coordinate into the inequality and test if they work.

Let's start with A, 5 being y and 0 being x .

5 > |0|+5\\5> 0+5\\5 > 5

5 IS NOT greater than 5, they are the exact same, so A is out.

Let's try B, 1 being x and 7 being y.

7 > |1| + 5\\7 > 1 + 5\\7 > 6

7 IS greater than 6, so B. (1,7) does work for this inequality!

Let's do C for fun, when 7 is x and 1 is y.

1 > |7| + 5\\1>7+5\\1>12

1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.

Therefore B. (1,7) works for the inequality of y > |x|+5.

Hope this helped!

7 0
3 years ago
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