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4 years ago

What are the numbers called in a multiplication

Mathematics

2 answers:

igomit [66]4 years ago

4 0

The two numbers you multiply are called factors and the answer is called the product

mart [117]4 years ago

3 0

The numbers that are called in multiplication are called factors. Multiplying factors together will create a product.

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Suppose a baseball team has 14 players on the roster who are not members of the pitching staff. Of those 14 players, assume that

Nadusha1986 [10]

Answer: Our required probability would be 0.70.

Step-by-step explanation:

Since we have given that

Number of players = 14

Number of players have recently taken a performance enhancing drug = 3

Number of players have not recently taken a performance enhancing drug = 14-3=11

Number of members chosen randomly = 5

We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.

P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)

So, P(X≥1)=1-P(X=0)

$P(X\geq 1)=1-^5C_0(\dfrac{11}{14})^5\\\\P(X\geq 1)=1-(0.786)^5\\\\P(X\geq 1)=0.70$

Hence, our required probability would be 0.70.

7 0

3 years ago

DaniilM [7]

Answer:

hi so im jeff wanna be my friends

Step-by-step explanation:

4 0

3 years ago

Blood type AB is the rarest blood type, occurring in only 4% of the population in the United States. In Australia, only 1.5% of

Naddik [55]

Answer:

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

Step-by-step explanation:

For each U.S. resident, there are only two outcomes possible. Either they have blood type AB, or they do not. This means that we can solve this problem using binomial probability distribution concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

In this problem, we have that:

50 U.S residents are sampled, so $n = 50$

4% of the U.S population has blood type AB, so $p = 0.04$ .

What is the probability that exactly 2 of the U.S. residents have blood type AB?

This is P(X = 2). So:

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{50,2}.(0.04)^{2}.(0.96)^{48} = 0.2762$

There is a 27.62% probability that exactly 2 of the U.S. residents have blood type AB.

5 0

3 years ago

0.18 in standard form

slamgirl [31]

Answer:

Well.. its already in standard form..

but even if u want u can write it as 8 X 10^(-1)

Step-by-step explanation:

Standard form is used for quite big decimal numbers

like : 0.2356

We can write it as 2.4 X 10^(-1)

5 0

3 years ago

H v is help me!!!!!!!!

Anon25 [30]

Answer:

He spent $15.51

Step-by-step explanation:

0.55x28.2=15.51

Hope this helps

^_^

8 0

2 years ago