Answer:
The first term should be positive
She did not distribute the -4 properly
She added 
to negative -4 instead of multiplying
Step-by-step explanation:
In order to tell where she is wrong we should solve the question our selves. we are going to get the following......
So now we see that the three things she did wrong are.
The first term should be positive
She did not distribute the -4 properly
She added to negative -4 instead of multiplying
Hope this helps :)
The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8
Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12
Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8
t^3 + 3 t^2 + 3 t + 1 (ANSWER)
The inequalities are matched with their correct graph respectively as follows:
- D ⇒ {(x, y): y > x²}.
- G ⇒ {(x, y): y ≥ x²+ 3
- C ⇒ {(x, y): y ≤ 3x² + 2}
- A ⇒ {(x, y): y ≥ 2x² - 5x + 1}
- J ⇒ x²- 3x ≥ 0
- H ⇒ x² - 3x + 2 ≤ 0
- B ⇒ {(x, y): y ≤ 1 - x²}
- B ⇒ {(x, y): y ≥ -1}
<h3>What is a graph?</h3>
A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.
<h3>What is an inequality?</h3>
An inequality can be defined as a mathematical relation that compares two (2) or more integers and variables in an equation based on any of the following arguments:
- Less than (<).
- Greater than (>).
- Less than or equal to (≤).
- Greater than or equal to (≥).
In Geometry, if the leading coefficient of a quadratic equation is greater than (>) zero, the parabolic curve would open upward while the parabolic curve would open downward when the leading coefficient of a quadratic equation is less than (<) zero.
Read more on graph of inequalities here: brainly.com/question/24372553
#SPJ1
Complete Question:
Match the questions with the graphs that are labeled A-H. (keep in mind that some questions might have the same answer)
1. A = {(x, y): y > x^2}
2. B = {(x, y): y ≥ x^2+ 3}
3. C = {(x, y): y ≤ 3x^2 + 2}
4. D = {(x, y): y ≥ 2x^2- 5x + 1}
6. x^2- 3x ≥ 0
7. x^2- 3x + 2 ≤ 0
8. {(x, y): y ≤ 1 - x^2}
9. {(x, y): y ≥ -1}
Answer:
Clara can feed 10 friend
I may be wrong, but I tried :P
X^2(x+2)-4(x+2)
(x^2-4) (x+2) = 0
do you have to keep going/?
or thats all they want?
