Use the following rules:
- The sum of currents that enter and exit a node (junction) is always zero. So if you have 3 wires that connect, through one flows 2A, the other 3A, then the third must deliver 5A (taking the direction into account!)
- The sum of voltages across different components should always add up. So if you have a battery of 10V with two unknown resistors, and over one of the resistors is 4V, you know the other one has the remaining 6V.
- With resistors, V=I*R must hold.
With these basic rules you should get a long way!
Answer:
public class Triangle
{
public static void main( String[] args )
{
show( 5 );
}
public static void show( int n )
{
int i,j,k;
for (i = 0; i < n - 1; i++ )
{
for (j = 0; j < i; j++ )
{
System.out.print( " " );
}
for (k = n - i; k > 0; k-- )
{
System.out.print( "* " );
}
System.out.println();
}
for (i = 0; i < n; i++ )
{
for (j = n - i; j > 1; j-- )
{
System.out.print( " " );
}
for (k = 0; k < i + 1; k++ )
{
System.out.print( "* " );
}
System.out.println();
}
Yes actually it is it’s a machine to use for opening bottles such as cans n other
4. Although all of them could be true, this one is most acurate :)
