Is there more than one pair that could be congruent?
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So, Anna has a markers, Ben has b markers and Cindy has c markers.
We know that a+b+c = m.
And we know also that a = 2b. (<span> twice as many markers as ben has</span>)
(Remember b is the number of Ben markers.)
The equation becomes:
2b+b+c=m.
Solving for c:
Cindy has (m-3b) markers.
We know that a+b+c = m.
And we know also that a = 2b. (<span> twice as many markers as ben has</span>)
(Remember b is the number of Ben markers.)
The equation becomes:
2b+b+c=m.
Solving for c:
Cindy has (m-3b) markers.