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2 years ago

Find the GCF of the following numbers:

Mathematics

1 answer:

Maurinko [17]2 years ago

6 0

Answer:

$2^53^5$

Step-by-step explanation:

So if we compare $2^5 \cdot 3^7$ to $2^7 \cdot 3^5$ , we should see the most amount of factors of 2 that they have in common is 5 and the most amount of factors of 3 that they have in common is 5.

If you aren't sure on the number of factors of 2 and 3 they have in common you could write it all out:

$2^53^7=(2)(2)(2)(2)(2)\cdot\text{ }(3)(3)(3)(3)(3)(3)(3$

$2^73^5=(2)(2)(2)(2)(2)(2)(2)\text{ }(3)(3)(3)(3)(3)$

So if I were able to circle each pair of 2's they had in common I would circle 5 pairs.

If were able to circle each pair of 3's they had in common I would circle 5 pairs.

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Fred is 5 inches shorter than the quotient of Rick’s height and 4. let r represent Rick’s height. Write an expression that repre

Sunny_sXe [5.5K]

Let r represent Rick’s height.
Therefore, the quotient of Rick’s height and 4
$= \frac{r}{4}$
Fred is 5 inches shorter than the quotient of Rick’s height and 4.
Therefore, an expression that represents Fred’s height is
$\frac{r}{4} - 5$

Answer:

$\frac{r}{4} - 5$

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0

2 years ago

Read 2 more answers

Only 8 9 and 10 please

sattari [20]

8) 3/16
9) 41/8
10) 218/5

3 0

3 years ago

If you get a sneak peak at the salary list of your job and realize you are in the lowest bracket, which is the lowest 1%, what i

hoa [83]

Answer:

$z=-2.33$

And if we solve for a we got

$a=48000 -2.33*5500=35185$

And for this case the answer would be 35185 the lowest 1% for the salary

Step-by-step explanation:

Let X the random variable that represent the salary, and for this case we can assume that the distribution for X is given by:

$X \sim N(48000,5500)$

Where $\mu=48000$ and $\sigma=5500$

And we want to find a value a, such that we satisfy this condition:

$P(X>a)=0.99$ (a)

$P(X$ (b)

We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.01 of the area on the left and 0.99 of the area on the right it's z=-2.33. On this case P(Z<-2.33)=0.01 and P(z>-2.33)=0.99

If we use condition (b) from previous we have this:

$P(X$