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Step2247 [10]
3 years ago
9

Find the value of a.

Mathematics
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

a=2x^3+2x^2−2x−2/x^3+x^2−x−1

Step-by-step explanation:

the explanation is very long and lengthy, let me know in the comments if you want it

hope this helps!

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Marizza181 [45]
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Find the volume of the cone shown, if r=8 cm and AC=AB=17 cm
Papessa [141]

Answer:

1005.3 cm³

Step-by-step explanation:

The radius of the cone (r) is 8 cm and the slant height is AC = AB = 17 cm.

Therefore, the height of the cone (h) will be given by \sqrt{17^{2} - 8^{2}} = \sqrt{225} = 15 cm.

We have to calculate the volume of the cone.

Therefore, the volume of the cone will be given by \frac{1}{3}\pi  r^{2}h

= \frac{1}{3} \times \frac{22}{7} \times 8^{2}\times 15

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3 years ago
The table shows information about the masses of some dogs. a) Work out the minimum number of dogs that could have a mass of more
V125BC [204]

Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Because the maximum number so lets assume that all dogs in 20≤x<30 are more then 27.

4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

To learn more about numbers visit: brainly.com/question/17429689

#SPJ1

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Round 169,750 to the nearest hundred thousand
Allushta [10]

Answer:

200,000

Step-by-step explanation:

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