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Reika [66]
3 years ago
5

Yasmine bought 6 gallons of apple juice after filling up 4 bottles of the same size with apple juice , she had 0.3 gallons of ap

ple juice left how many gallons of apple juice are in each container
Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0
The answer should be 1.425.
Once you subtract 0.3 from 6 it leaves you with 5.7
then do 5.7 divided by 4 and you would get 1.425
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This solid shape is made from 5 cubes.
expeople1 [14]

Answer:

what is the question?

Step-by-step explanation:

3 0
2 years ago
(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each
Leviafan [203]

Following are the solution parts for the given question:

For question A:

\to (n) = 16

\to (\bar{X}) = 410

\to (\sigma) = 40

In the given question, we calculate 90\% of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}

\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\

Using the t table we calculate t_{ \frac{\alpha}{2}} = 1.753  When 90\% of the confidence interval:

\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53

So 90\% confidence interval for the mean weight of shipped homemade candies is between 392.47\ \ and\ \ 427.53.

For question B:

\to (n) = 500

\to (X) = 155

\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31

Here we need to calculate 90\% confidence interval for the true proportion of all college students who own a car which can be calculated as

\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}

\to C.I= 0.90

\to (\alpha) = 0.10

\to \frac{\alpha}{2} = 0.05

Using the Z-table we found Z_{\frac{\alpha}{2}} = 1.645

therefore 90\% the confidence interval for the genuine proportion of college students who possess a car is

\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344

So 90\% the confidence interval for the genuine proportion of college students who possess a car is between 0.28 \ and\ 0.34.

For question C:

  • In question A, We are  90\% certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
  • In question B, We are  90\% positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:  

brainly.in/question/16329412

7 0
2 years ago
Sam runs 2 miles in 16 minutes. If Sam runs at the same rate, how far can he run in 64 minutes?
Pie

Answer:

8 miles

Step-by-step explanation:

Since

16 x 4 = 64

Therefore

2 x 4 = 8

8 miles

5 0
3 years ago
а Ava and her children went into a movie theater and she bought $48 worth of drinks and candies. Each drink costs $4 and each ca
adoni [48]

Answer:

x = 6

y = 8

Explanation and graph is given in picture

I hope it helps.

6 0
2 years ago
Please help and for number 2
prohojiy [21]
Area = 1/2 x B x H
1/2 x 28.3 x 12.8 = 181.12

Answer is #3
7 0
3 years ago
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