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Verdich [7]
3 years ago
13

Find the value of 5(a-4b) when a=-7 and b=1/4

Mathematics
2 answers:
V125BC [204]3 years ago
4 0

Answer:

-64

Step-by-step explanation:

VLD [36.1K]3 years ago
4 0

Answer:-36

Step-by-step explanation:

5x-7-4x1/4

5a=-35

coz 5x-7=-35

4b=1

coz 4x1/4=1

-35-1=-36

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Answer:

30

Step-by-step explanation:

5*2*3-2*0 ( when we multiply any number with zero then the result is also zero)

30-0

30

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Answer:

A

Step-by-step explanation:

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The sum of 5 consecutive odd integers is 2,555. What is the sum of the first, third, and last integer?
Lilit [14]

Answer:

The sum of the first, third, and last integer is 1533.

Step-by-step explanation:

<u><em>Step 1: You need to create a equation first:</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

<u><em>How did I make the equation?</em></u>

If n is odd number, n + 2 must be the consecutive odd number

5 , 5 + 2 , 5 + 4 , 5 + 6 , 5 + 8

5, 7, 9, 11, 13  ALL CONSECUTIVE ODD NUMBERS

<u><em>Step 2: Simplifying the equation</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8 = 2555

5n + 20 = 2555

<u><em>Step 3: Solving the equation, with explanation</em></u>

5n + 20 = 2555       Subtract 20 on both sides

        5n = 2535        Isolate the variable by dividing 5 on both sides

          n = 507

<u><em></em></u>

<u><em>Step 4: Plug in the value</em></u>

n + n + 2 + n + 4 + n + 6 + n + 8

507,  507 + 2 , 507 + 4 , 507 + 6 , 507 + 8

507, 509, 511, 513, 515

<u><em>Step 5:  Solve the sum of the first, third, and last integer</em></u>

507 + 511 + 515 = 1533

<u><em>Step 6: THE ANSWER</em></u>

1533

<h3><u><em>Hope this helps!!! </em></u></h3><h3><u><em>Please mark this as brainliest!!! </em></u></h3><h3><u><em>Thank You!!! </em></u></h3><h3><u><em>:)</em></u></h3>
8 0
3 years ago
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-(1/4)*x+b
b=2-(-1/4)*8
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