All categories

2 years ago

Which expression is equivalent to (r^-7)^8

Mathematics

1 answer:

ahrayia [7]2 years ago

6 0

Answer:

1/r^56

Step-by-step explanation:

Not sure if you did a typo there or what cus 7 x 8 should be 56

Whenever the power of a number is negative, you flip. So r^-7 becomes 1/r^7

Remove the bracket and distribute 8 to the power of 1 and r^7

1 to the power of 8 will still be 1, r^7 x 8 = r ^ 56

You might be interested in

Matt Ali deposited $25,000 in a savings account. The account earns 5.5 percent interest compounded daily. Use the formula “ Amou

katen-ka-za [31]

Answer:

A) Amount = $ 116,601.31

B) Compound Interest = $ 91,601.31

Step-by-step explanation:

Compound interest Formula

A = P(1 + r/n)^nt

Where

P = Initial amount invested = $25,000

r = interest rate = 5.5 %

n = Compounding frequency = daily

t = time in years = 28 years

A). What amount will he have in his account 28 years later ?

First, convert R percent to r a decimal

r = R/100

r = 5.5%/100

r = 0.055 per year,

Then, solve our equation for A

A = P(1 + r/n)^nt

A = 25,000.00(1 + 0.000150685/365)^(365)(28)

A = $ 116,601.31

B.) How much will be compound interest ?

I = Amount - Principal

A(Amount ) = $ 116,601.31

P (principal) = $ 25,000.00

I = $ 116,601.31 - $ 25,000.00

I (interest) = $ 91,601.31

6 0

3 years ago

Y = 5x + 8; if x = 3 helppp

Katyanochek1 [597]

Y = 5 x 3 + 8
y = 15 + 8
y = 23

3 0

3 years ago

Read 2 more answers

What is the value of the discriminante for the quadratic equation 0=2x^+x-3

denpristay [2]

Answer:

x1= 1 , x2 = (-1.5)

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me ;}

8 0

3 years ago

Cause and effect please help ?

seraphim [82]

The effect on the photos perimeter and area would be that the resulting photo would be larger than intended.

5 0

3 years ago

Evaluate the upper and lower sums for f(x) = 1 + x2, −1 ≤ x ≤ 1, with n = 3 and 4.

Elenna [48]

I'm going to assume that your function is f(x) = 1 + x^2 (NOT x2).

I suspect you're trying to estimate the "area under the curve of f(x) = 1 + x^2. You need to use this or a similar description to explain what you're doing.

Also, you need to specify whether you want "left end points" or "right end points" or "midpoints." Again I must assume you want one or the other (and will assume that you meant "left end points").

First, let's address the case n=3. You must graph f(x) = 1 + x^2 between -1 and +1. We will find the "lower sum," using "left end points." The 3 x-values are {-1, -1/3, 1/3}. Evaluate the function f(x) = 1 + x^2 at these 3 x-values. Keep in mind that the interval width is 2/3.
The function (y) values are {0, 2/3, 4/3}.

Sorry, Michael, but I must stop here and await clarification from you regarding what you've been told to do in this problem. Otherwise too much guessing (regarding what you meant) is necessary. Please review the original problem and ensure that you have copied it exactly as presented, and also please verify whether this problem does indeed involve estimating areas under curves between starting and ending x-values.

7 0

3 years ago