Question

a fish tank in the shape of a rectangular prism measures 100 x 60 x 40/The water level reached the midpost of the base (50cm mark) when the tank was tilted to rest on a 60cm edge. What would be the depth of the water, if the tank is returned to its horizontal position (resting on a 60x100 base)?

Answer 1

Answer:

Step-by-step explanation:

volume of water

$=\frac{1}{2}*50*40*60=60000 ~cm^3$

when the base is 100×60

let h be depth of water.

100×60×h=60000

h=60000/6000=10 cm.