The height of the isosceles triangle is 8.49 inches.
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How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
brainly.com/question/2217700
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P(G) is 26/52
P(H) is 8/52
See the rest in the photo
Answer: 4(5j+7) = 20j+28
Step-by-step explanation:
The length of an arc subtended by a central angle is proportional to the circle's circumference. If the given central angle has measure 
and the circle has radius 
, then the arc has length 
such that
where is given in radians. Then
If is given in degrees, then
