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alina1380 [7]
2 years ago
8

How much larger is the volume of cylinder when you quadruple the radius of the base?

Mathematics
1 answer:
Snowcat [4.5K]2 years ago
8 0

Answer:

siygxuyasvc

Step-by-step explanation:

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Please Help Me:!!!!!
butalik [34]

Answer:

Vertical stretch of factor of 3

translated to the right 2

translated up 5

Step-by-step explanation:

6 0
3 years ago
Please find missing side length, only if you know seriously
frez [133]
Ok so it’s 6.93 or 7 if u wanna round it
It’s the a^2+b^2=c^2
5 0
3 years ago
Read 2 more answers
What is the least number of cuts you would need to make to cut a 3 by 3 by 3 inch block of cheese into 1 by 1 by 1 inch blocks o
Semenov [28]

Answer:

6 Cut Minimum

Step-by-step explanation:

According to the Question,

You have a 3x3x3 cube.

  1. First make two cuts parallel to base of the cube each at a distance of 1 unit . This leaves you with three cuboids of dimensions 3x3x1.
  2. Now make two parallel cuts parallel to the height of the cube. This leaves you with nine cuboids of dimensions 3x1x1.
  3. Now make the final two cuts each 1 unit apart parallel to width and you are left with 27 cubes of 1x1x1.

So , the final answer is 6 cuts.

5 0
3 years ago
Hayley had 3.93 grams of salt. She added more salt to the sample and now has 4.87 grams. How many grams of salt did Hayley add?
Alik [6]
You subtract the intial from the final. your answer is0.94grams
3 0
3 years ago
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a sequence has a first number of 3 and a half common difference of 4 what is the recursive rule of nth term​
ELEN [110]

Answer:

f(n) = f(n-1) + 8 for n > 1

Step-by-step explanation:

Given

f(1) = 3 -- First Term

\frac{1}{2}d = 4 --- half common difference

Required

Find the recursive rule

First, we calculate the common difference

\frac{1}{2}d = 4

Multiply through by 2

2 * \frac{1}{2}d = 2 * 4

d = 8

The second term of the sequence is:

f(2) = 3 + 8 = 11

The third term is:

f(3) = 11 + 8 = 20

So, we have:

f(1) = 3

f(2) = 3 + 8

Substitute f(1) for 3

f(2) = f(1) + 8

Express 1 as 2 - 1

f(2) = f(2-1) + 8

Substitute n for 2

f(n) = f(n-1) + 8

Similarly:

f(3) = 11 + 8

Substitute f(2) for 11

f(3) = f(2) + 8

Express 2 as 3 - 1

f(3) = f(3-1) + 8

Substitute n for 3

f(n) = f(n-1) + 8

Hence, the recursive is:

f(n) = f(n-1) + 8 for n > 1

8 0
2 years ago
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