You have the polygon MNOPQR which can be expressed as two rectangles pasted one next to each other.
To see the two rectangles in the picture, you can draw a line parallel to segment MR througn point N.
From the original picture you can state the dimensions of both rectangles.
Call S, the point where the line that you drew intercepts the segment RQ.
Then one rectangle is MNSR and the other rectangle is OPQS.
The measures of the sides of the rectangle MNSR are:
- the length of MN = length of SR = base
- the length of MR = the length of NS.= height
So its area is base * height, which you can all A1.
The measured of the rectangle OPQS are:
- segment OP = segment SQ = segment QR - segment SR = base
- segment PQ = segment OS = height
So its area is base * height, which you can call A2.
Then the area of the polygon MNOPQRS is A1 + A2. One of them is 9 u^2 and the other is what the answer is asking for, and that you have calculated above.
With this procedure you can tell the value needed.
Answer: Line AC = 36
Step-by-step explanation: The first and most important clue is the fact that points B, D and F are midpoints of the triangle ACE. What this tells us is that point B divides line AC into two equal sides. Likewise points D and F. If point D divides line EC into two equal sides, then line ED equals
39/2 = 19.5
Also, triangle FED is similar to triangle AEC. Since ED is half of EC, and FE is half of AE. Therefore in triangles FED and AEC,
FD/ED = AC/EC
18/19.5 = AC/39
By cross multiplication we now have
(18 x 39)/19.5 = AC
702/19.5 = AC
36 = AC
Therefore line AC = 36
Answer:
Step-by-step explanation:
I think option 4 is the correct answer
No, 1 hole pie is = 10/10.
so if 5 people each take 2/10 that is equal to
2/10 x 5 = 10/10 thus 1
so none of the pie is left
Answer:
8
Step-by-step explanation:
Using the Law of Sines,
b/sin B = a/sin A
b/sin(37.81°) = 12/sin(113.17°)
b=(12sin(37.81°))/(sin(113.17°), which is about 8.