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pav-90 [236]
2 years ago
14

Elimination Method: 6x - 4y = -24 and 4x + 5y = -2

Mathematics
1 answer:
nirvana33 [79]2 years ago
4 0

Answer:

(-2;-6)

Step-by-step explanation:

First of all, let's rewrite the first one after dividing both sides by 2.

\left \{ {{3x-2y=-12\atop {4x+5y=-2}} \right.

Now, let's pick one you want to eliminate.

<u>Eliminating x:</u> Let's multiply the first one by 4, the second by 3, and subtract one from the other. Rest is simply solving an equation in one variable

4I-3II : 12x-8y-12x+15y = -48 - (-6)\\7y = -42 \rightarrow y= -6

<u>Eliminating y:</u> Let's multiply the first by 5, the second by 2, and add them together. Rest is simply solving an equation in one variable

5I+2II: 15x -10y +8x +10y = -60 +4\\23x = -56 \rightarrow x=-2

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Answer:

The population will reach 34,200 in February of 2146.

Step-by-step explanation:

Population in t years after 2012 is given by:

P(t) = 0.8t^{2} + 6t + 19000

In what month and year will the population reach 34,200?

We have to find t for which P(t) = 34200. So

P(t) = 0.8t^{2} + 6t + 19000

0.8t^{2} + 6t + 19000 = 34200

0.8t^{2} + 6t - 15200 = 0

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

0.8t^{2} + 6t - 15200 = 0

So a = 0.8, b = 6, c = -15200

Then

\bigtriangleup = 6^{2} - 4*0.8*(-15100) = 48356

t_{1} = \frac{-6 + \sqrt{48356}}{2*0.8} = 134.14

t_{2} = \frac{-6 - \sqrt{48356}}{2*0.8} = -141.64

We only take the positive value.

134 years after 2012.

.14 of an year is 0.14*365 = 51.1. The 51st day of a year happens in February.

So the population will reach 34,200 in February of 2146.

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