Elimination Method: 6x - 4y = -24 and 4x + 5y = -2
1 answer:
Answer:
Step-by-step explanation:
First of all, let's rewrite the first one after dividing both sides by 2.
Now, let's pick one you want to eliminate.
<u>Eliminating x:</u> Let's multiply the first one by 4, the second by 3, and subtract one from the other. Rest is simply solving an equation in one variable
<u>Eliminating y:</u> Let's multiply the first by 5, the second by 2, and add them together. Rest is simply solving an equation in one variable
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When x =170, y =10, when x = 187, y = 1, when x = 204, y = 12, when x = 221, y = 13, when x = 238, y = 14, when x = 255, y = 15, when x = 272, y = 16, when x = 289, y = 17, when x = 306, y = 18, when x = 323, y = 19, when x = 340, y = 20,
Step-by-step explanation:
Step 1; Assume y is the gallons in the tank while x is the range of the car. We need to determine the equation relating the y to the x values in the given coordinates. x is the dependent value whereas y is the independent value i.e. the value of x depends on the value of y.
Step 2; As y increases, x also increases. For every extra gallon in the tank, the car can go another 17 miles. So with y as the amount of gas in the tank in gallons and x as the range of vehicle, we get;
x = 17y, this represents the relation between x and y.
To find the gallons in the tank, y = ,
For x = 170, y = = 10,
Similarly equating the values we get that when x = 187, y = 11,
when x = 204, y = 12,
when x = 221, y = 13,
when x = 238, y = 14,
when x = 255, y = 15,
when x = 272, y = 16,
when x = 289, y = 17,
when x = 306, y = 18,
when x = 323, y = 19,
when x = 340, y = 20,