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3 years ago

Which graph does it represent a function?

Mathematics

2 answers:

Rina8888 [55]3 years ago

3 0

Answer:

The graph in the bottom right (The circle) is not a function

Step-by-step explanation:

As the circle has multiple y values for each x value, it is not a function. In other words, that graph fails the vertical line test.

DaniilM [7]3 years ago

3 0

Answer:

IV graph

Step-by-step explanation:

Function: It is relation between x and y.For each x, there is a unique value of y.

Only one output for one input.

One value of x cannot have more than one images.

Vertical line test:

When we draw a vertical line passing through any given value of x and cut the curve more than one points then, the curve does not represents the function.

When a vertical line cuts the curve at one point then, the curve represents the function.

In I graph, We can see that

Image of 1 is 2.

Image of 2 is 1.

Image of -2 is 1.

There is only one output for input.

Hence, it represents the function.

In II graph,

By vertical line test, when we draw a vertical line x=1 then it cuts the graph at one point only.

Hence, it represents the function.

In III graph,

Image of 1 is 1.

Image of 0 is 2.

Image of -1 is 3.

Image of -2 is 4.

There is only one output for 1 input.

Hence, it represents the function.

In IV graph,

When we draw a vertical line x=1 then , it cuts the curve at two points.

Therefore, given circle does not represents the function.

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ahrayia [7]

2x + 8 would be the simplified version of this question

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3 years ago

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(2) The population density of a region in Alaska is 3,000 people/200 mi? Which of the

Vesna [10]

Answer:

15 people/mi

Step-by-step explanation:

The population density of a region in Alaska is 3,000 people/200 mi.

We need to find the equivalent to the population density of this Alaskan region.

$x=\dfrac{3000\ \text{people}}{200\ \text{mi}}\\\\x=\dfrac{30\ \text{people}}{2\ \text{mi}}\\\\x=\dfrac{15\ \text{people}}{\text{mi}}$

So, the correct option is (c) "15 people/mi"

8 0

3 years ago

You are dealt two cards successfuly without replacement from a shuffled deck of 52 playing card. Find the probability that first

katen-ka-za [31]

The simplified expression is $(\frac{4}{663})$

Step-by-step explanation:

Here, the total number of cards in a given deck = 52

let E : Event of drawing a first card which is King

Total number of kings in the given deck = 4

So, $P(E) = \frac{\textrm{The total number of king}}{\textrm{The total number of cards}}$ = $\frac{4}{52} = (\frac{1}{13} )$

Now, as the picked card is NOT REPLACED,

So, now the total number of cards = 52 - 1 = 51

Total number of queen in the deck is same as before = 13

let K : Event of drawing a second card which is queen

So, $P(K) = \frac{\textrm{The total number of queen}}{\textrm{The total number of cards}}$ = $(\frac{4}{51} )$

Now, the combined probability of picking first card as king and second as queen = P(E) x P(K) = $(\frac{1}{13}) \times(\frac{4}{51}) = (\frac{4}{663} )$

Hence, the simplified expression is $(\frac{4}{663})$

6 0

3 years ago

Sole m-2/12=1/6 a.4 b.1 c.0 d.2

riadik2000 [5.3K]

The answer would be A. 4
Here’s what I would do.
Multiply both sides by 12 so u can get m- 2 by itself.
m-2= 2
How’d I get the two? It comes from when I multiplied 12 on both sides. 12/6= 2
Now ur equation should be
m-2=2
Do the opposite and add two to both sides to get the variable by itself.
m=4

Hope this helps :)))

7 0

3 years ago

Find the zeros of the function.

Zigmanuir [339]

Answer:

x = 3, x = 4

Step-by-step explanation:

To find the zeros of the function, equate f(x) to zero, that is

(x - 3)(2x - 8) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3 ← smaller solution

2x - 8 = 0 ⇒ 2x = 8 ⇒ x = 4 ← larger solution

5 0

3 years ago