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AleksAgata [21]
3 years ago
14

Ayudaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Mathematics
2 answers:
Lesechka [4]3 years ago
6 0

Answer:

Whats in the docx. I don't want to open it.

Step-by-step explanation:

Nady [450]3 years ago
5 0

Answer:

Okay, hello to you too.

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16 POINTS HELP ASAP plzzzzzzzzz
schepotkina [342]

Answer:

                            \large\boxed{\large\boxed{\sqrt{3}

Explanation:

You are comparing irrational numbers.

By inspection, i.e. at first sight you can only compare \sqrt{3} \text{ }and\text{ } 2\sqrt{3} because they have the same radicand.

You can order: \sqrt{3}

You can introduce the 2 inside the radical by squaring it:

       2\sqrt{3}=\sqrt{2^2\times3}=\sqrt{12}

Since 5 is between 3 and 12, you can order:

  • \sqrt{3}

Which is:

  • \sqrt{3}

You must know that π ≈ 3.14.

5 is less than 9 and the square root of 9 is 3; hence, \sqrt{5} and \sqrt{5}

Now you must determine whether π is less than or greater than \sqrt{12}

Using a calculator or probing numbers between 3 and 4 you get \sqrt{12} \approx3.46

Hence, the complete order is:

  •            \sqrt{3}
5 0
3 years ago
Coral created a painting that was 4 1/ 3  ft long and 1 1/ 5  ft wide. What was the area of Corals painting? Express your answer
kotegsom [21]
!! Answer will be C !!
8 0
3 years ago
The factors of 6x-30 are ?
Tju [1.3M]
So you have 6x-30. The only factor I can think of for this is x+5. Because you have 6(x+5)= 6x+30
5 0
3 years ago
Read 2 more answers
HELP PLEASE <br><br> Need help on this problem
JulijaS [17]

Answer:

Let's use the Pythagorean theorem!! I think there are two correct answers, right?

5 0
3 years ago
VERY EASY WILL GIVE BRAINLEST THANK YOU AND FRIEND YOU Determine whenter (18+35)x4= 18+35x4 is true or false. Explain.
Ray Of Light [21]

Answer:

False because on the left side of the equation you are adding 18 and 35 first and on the right you are multiplying 35 and 4 first. This will give you an unequal equation when solved.

Let's solve each side

(18+35)*4=212

but 18+(35*4)=158

8 0
3 years ago
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